`CH_(3)-CH_(2)-CH=CH_(2)` has hybridisation :

Options

A. `sp,sp,sp^(2),sp^(2)`
B. `sp^(3),sp^(3),sp^(2),sp`
C. `sp^(3),sp^(3),sp^(2),sp^(2)`
D. `sp^(3),sp^(2),sp^(2),sp`

Answer

To determine the hybridization of the compound CH₃-CH₂-CH=CH₂, we can follow these steps:

### Step 1: Identify the Structure
The compound CH₃-CH₂-CH=CH₂ consists of four carbon atoms connected in a chain, with a double bond between the third and fourth carbon atoms.

### Step 2: Draw the Lewis Structure
We can draw the Lewis structure to visualize the bonding:
- The first carbon (C1) is bonded to three hydrogens (H) and one carbon (C2).
- The second carbon (C2) is bonded to two hydrogens (H) and two carbons (C1 and C3).
- The third carbon (C3) is bonded to one hydrogen (H) and two carbons (C2 and C4).
- The fourth carbon (C4) is bonded to two hydrogens (H) and one carbon (C3).

### Step 3: Determine the Hybridization of Each Carbon
1. **C1 (CH₃)**:
- It forms four single bonds (3 C-H and 1 C-C).
- Hybridization: **sp³** (4 sigma bonds).

2. **C2 (CH₂)**:
- It forms three sigma bonds (2 C-H and 1 C-C).
- Hybridization: **sp³** (3 sigma bonds).

3. **C3 (CH)**:
- It forms three sigma bonds (1 C-H and 2 C-C) and has one double bond with C4.
- Hybridization: **sp²** (1 double bond + 2 sigma bonds).

4. **C4 (CH₂)**:
- It forms three sigma bonds (2 C-H and 1 C-C).
- Hybridization: **sp²** (1 double bond + 2 sigma bonds).

### Step 4: Compile the Hybridization Results
- C1: sp³
- C2: sp³
- C3: sp²
- C4: sp²

### Conclusion
The hybridization of the compound CH₃-CH₂-CH=CH₂ is **sp³, sp³, sp², sp²**.

### Final Answer
The correct option is **Option 3: sp³, sp³, sp², sp²**.

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