Which of the following is an example of super octet molecule ?

Options

A. `ClF_(3)`
B. `PCl_(5)`
C. `IF_(7)`
D. All the three

Answer

To determine which of the following is an example of a super-octet molecule, we first need to understand what a super-octet is. A super-octet molecule has more than 8 electrons surrounding the central atom.

### Step-by-Step Solution:

**Step 1: Define Super-Octet**
- A super-octet refers to a molecule where the central atom has more than 8 electrons in its valence shell.

**Step 2: Analyze ClF3**
- Chlorine (Cl) has 7 valence electrons.
- In ClF3, chlorine forms bonds with 3 fluorine atoms, sharing 3 electrons.
- Total electrons around Cl = 7 (own) + 3 (shared) = 10 electrons.
- Conclusion: ClF3 is a super-octet molecule.

**Step 3: Analyze PCl5**
- Phosphorus (P) has 5 valence electrons.
- In PCl5, phosphorus forms bonds with 5 chlorine atoms, sharing 5 electrons.
- Total electrons around P = 5 (own) + 5 (shared) = 10 electrons.
- Conclusion: PCl5 is also a super-octet molecule.

**Step 4: Analyze IF7**
- Iodine (I) has 7 valence electrons.
- In IF7, iodine forms bonds with 7 fluorine atoms, sharing 7 electrons.
- Total electrons around I = 7 (own) + 7 (shared) = 14 electrons.
- Conclusion: IF7 is also a super-octet molecule.

**Step 5: Final Conclusion**
- All three molecules: ClF3, PCl5, and IF7 have more than 8 electrons surrounding their central atoms.
- Therefore, all three are examples of super-octet molecules.

### Final Answer:
ClF3, PCl5, and IF7 are all examples of super-octet molecules.