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How many resonance structures can be dra...

How many resonance structures can be drawn for the nitrate ion, `NO_3^(-)`?

A

1

B

2

C

3

D

4

Text Solution

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The correct Answer is:
To determine how many resonance structures can be drawn for the nitrate ion, \( \text{NO}_3^{-} \), we can follow these steps: ### Step 1: Draw the Lewis Structure of the Nitrate Ion 1. Count the total number of valence electrons: - Nitrogen (N) has 5 valence electrons. - Each Oxygen (O) has 6 valence electrons, and there are three Oxygens: \( 3 \times 6 = 18 \). - The negative charge adds 1 extra electron. - Total: \( 5 + 18 + 1 = 24 \) valence electrons. 2. Arrange the atoms: - Place nitrogen in the center and surround it with three oxygen atoms. 3. Distribute the electrons: - Start by forming single bonds between nitrogen and each oxygen (3 single bonds use 6 electrons). - Distribute the remaining electrons to satisfy the octet rule for oxygen atoms. 4. Form a double bond: - To satisfy the octet rule for nitrogen, one of the oxygen atoms will form a double bond with nitrogen, while the other two will have single bonds and carry a negative charge. ### Step 2: Identify Possible Resonance Structures 1. The first resonance structure can be represented as: - \( \text{N} \) with a double bond to one \( \text{O} \) (let's say \( \text{O}_1 \)), and single bonds to the other two \( \text{O} \) atoms (\( \text{O}_2 \) and \( \text{O}_3 \)), where \( \text{O}_2 \) and \( \text{O}_3 \) carry negative charges. 2. Shift the double bond to another oxygen: - In the second resonance structure, \( \text{N} \) will have a double bond with \( \text{O}_2 \) and single bonds with \( \text{O}_1 \) and \( \text{O}_3 \). 3. Shift the double bond to the third oxygen: - In the third resonance structure, \( \text{N} \) will have a double bond with \( \text{O}_3 \) and single bonds with \( \text{O}_1 \) and \( \text{O}_2 \). ### Step 3: Count the Resonance Structures - After drawing all possible structures, we find that there are three resonance structures for the nitrate ion. ### Conclusion The total number of resonance structures that can be drawn for the nitrate ion \( \text{NO}_3^{-} \) is **3**. ---

To determine how many resonance structures can be drawn for the nitrate ion, \( \text{NO}_3^{-} \), we can follow these steps: ### Step 1: Draw the Lewis Structure of the Nitrate Ion 1. Count the total number of valence electrons: - Nitrogen (N) has 5 valence electrons. - Each Oxygen (O) has 6 valence electrons, and there are three Oxygens: \( 3 \times 6 = 18 \). - The negative charge adds 1 extra electron. - Total: \( 5 + 18 + 1 = 24 \) valence electrons. ...
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