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The molecule exhibiting maximum number o...

The molecule exhibiting maximum number of non-bonding electron pairs (l.p.) around the central atom is :

A

`XeOF_(4)`

B

`XeO_(2)F_(2)`

C

`XeF_(3)^(-)`

D

`XeO_(3)`

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AI Generated Solution

The correct Answer is:
To find the molecule exhibiting the maximum number of non-bonding electron pairs (lone pairs) around the central atom, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Molecules**: We will analyze the following molecules: - XeOF4 - XeO2F2 - Fe3- - XeO3 2. **Calculate Total Valence Electrons**: For each molecule, we will calculate the total number of valence electrons by adding the valence electrons of each atom present in the molecule. - **For XeOF4**: - Xe: 8 electrons - O: 6 electrons - F: 7 electrons × 4 = 28 electrons - Total = 8 + 6 + 28 = 42 electrons - **For XeO2F2**: - Xe: 8 electrons - O: 6 electrons × 2 = 12 electrons - F: 7 electrons × 2 = 14 electrons - Total = 8 + 12 + 14 = 34 electrons - **For Fe3-**: - Fe: 7 electrons × 3 = 21 electrons (since there are 3 Fe atoms) - Additional electron for the -3 charge = 1 electron - Total = 21 + 1 = 22 electrons - **For XeO3**: - Xe: 8 electrons - O: 6 electrons × 3 = 18 electrons - Total = 8 + 18 = 26 electrons 3. **Calculate Bond Pairs and Lone Pairs**: Using the formula: - Number of bond pairs = Total valence electrons / 8 - Remainder = Total valence electrons % 8 - Number of lone pairs = Remainder / 2 - **For XeOF4**: - Bond pairs = 42 / 8 = 5 (5 bond pairs) - Remainder = 42 % 8 = 2 - Lone pairs = 2 / 2 = 1 lone pair - **For XeO2F2**: - Bond pairs = 34 / 8 = 4 (4 bond pairs) - Remainder = 34 % 8 = 2 - Lone pairs = 2 / 2 = 1 lone pair - **For Fe3-**: - Bond pairs = 22 / 8 = 2 (2 bond pairs) - Remainder = 22 % 8 = 6 - Lone pairs = 6 / 2 = 3 lone pairs - **For XeO3**: - Bond pairs = 26 / 8 = 3 (3 bond pairs) - Remainder = 26 % 8 = 2 - Lone pairs = 2 / 2 = 1 lone pair 4. **Compare the Number of Lone Pairs**: - XeOF4: 1 lone pair - XeO2F2: 1 lone pair - Fe3-: 3 lone pairs - XeO3: 1 lone pair 5. **Conclusion**: The molecule with the maximum number of non-bonding electron pairs (lone pairs) around the central atom is **Fe3-**, which has **3 lone pairs**. ### Final Answer: The molecule exhibiting the maximum number of non-bonding electron pairs (lone pairs) around the central atom is **Fe3-**. ---
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VK JAISWAL ENGLISH-CHEMICAL BONDING (BASIC)-SUBJECTIVE PROBLEMS
  1. The molecule exhibiting maximum number of non-bonding electron pairs (...

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  2. Consider following compounds A to E : (A) XeF(n) " " (B) XeF((n+1)...

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  3. Consider the following five group (According to modern periodic table)...

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  4. Consider the following species and find out total number of species wh...

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  5. Consider the following table regarding interhalogen compounds, XY(n) (...

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  6. What is covalency of chlorine atom in second excited state ?

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  7. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  8. Calculate the value of X-Y, for XeOF(4). (X=Number of sigma bond pair ...

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  9. The molecule ABn is planar with six pairs of electrons around A in the...

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  10. Calculate value of (X+Y+Z)/(10), here X is O-N-O bond angle in NO(3)^(...

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  11. Calculate x+y+z for H(3)PO(3) acid, where x is no. of lone pairs, y is...

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  12. How many right angle, bond angles are present in TeF(5)^(-) molecular ...

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  13. How may possible angle FSeF bond angles are present in SeF(4) molecule...

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  14. In IF(6)^(-) and TeF(5)^(-), sum of axial d-orbitals which are used in...

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  15. Among the following, total no. of planar species is : (i) SF(4) " "...

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  16. Calculate the value of " x+y-z" here x,y and z are total number of non...

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  17. Consider the following table Then calculate value of "p+q+r-s-t".

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  18. In phosphorus acid, if X is number of non bonding electron pairs. Y is...

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  19. Calculate the number of p(pi)-d(pi) bond(s) present in SO(4)^(2-) :

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  20. Sum of sigma and pi bonds in NH(4)^(+) cation is ..

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  21. Consider the following orbitals (i)3p(x) (ii)4d(z^(2)) (iii)3d(x^(2)...

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