The shapes of `XeF_(4),XeF_(5)^(-) and SnCl_(2)` are :

Options

A. octahedral, trigonal bipyramidal and bent
B. square pyramidal, pentagonal planar and linear
C. square planar, pentagonal planar and angular
D. see-saw, T-shaped and linear

Answer

To determine the shapes of the molecules `XeF4`, `XeF5^-`, and `SnCl2`, we will follow a systematic approach using the concept of hybridization and the VSEPR (Valence Shell Electron Pair Repulsion) theory.

### Step 1: Determine the Hybridization and Shape of `XeF4`
1. **Identify the central atom and its valence electrons**:
- Xenon (Xe) is the central atom and has 8 valence electrons.

2. **Count the number of monovalent atoms attached**:
- There are 4 fluorine (F) atoms attached to xenon.

3. **Calculate the steric number**:
- Using the formula:
\[ \text{Steric Number} = \frac{1}{2} \left( V + M + \text{Charge} \right) \]
where \( V = 8 \) (valence electrons of Xe), \( M = 4 \) (attached F atoms), and the charge is 0 (neutral molecule).
\[ \text{Steric Number} = \frac{1}{2} (8 + 4 + 0) = \frac{12}{2} = 6 \]

4. **Determine the hybridization**:
- A steric number of 6 corresponds to `sp^3d^2` hybridization.

5. **Identify the shape**:
- With 4 bond pairs and 2 lone pairs, the geometry is octahedral, but the actual shape is square planar.

### Step 2: Determine the Hybridization and Shape of `XeF5^-`
1. **Identify the central atom and its valence electrons**:
- Xenon (Xe) again is the central atom with 8 valence electrons.

2. **Count the number of monovalent atoms attached**:
- There are 5 fluorine (F) atoms attached.

3. **Account for the charge**:
- Since it is an anion, we add 1 to the total count.

4. **Calculate the steric number**:
- Using the formula:
\[ \text{Steric Number} = \frac{1}{2} (8 + 5 + 1) = \frac{14}{2} = 7 \]

5. **Determine the hybridization**:
- A steric number of 7 corresponds to `sp^3d^3` hybridization.

6. **Identify the shape**:
- With 5 bond pairs and 2 lone pairs, the shape is pentagonal planar.

### Step 3: Determine the Hybridization and Shape of `SnCl2`
1. **Identify the central atom and its valence electrons**:
- Tin (Sn) is the central atom and has 4 valence electrons.

2. **Count the number of monovalent atoms attached**:
- There are 2 chlorine (Cl) atoms attached.

3. **Calculate the steric number**:
- Using the formula:
\[ \text{Steric Number} = \frac{1}{2} (4 + 2 + 0) = \frac{6}{2} = 3 \]

4. **Determine the hybridization**:
- A steric number of 3 corresponds to `sp^2` hybridization.

5. **Identify the shape**:
- With 2 bond pairs and 1 lone pair, the shape is bent or angular.

### Summary of Shapes
- `XeF4`: Square planar
- `XeF5^-`: Pentagonal planar
- `SnCl2`: Bent or angular

### Final Answer
The shapes of `XeF4`, `XeF5^-`, and `SnCl2` are square planar, pentagonal planar, and bent (angular), respectively.

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