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Which is correct statement ? As the s-...

Which is correct statement ?
As the s-character of a hybrid orbital decreases
(I) The bond angle decreases (II) The bond strength increases
(III) The bond length increases (IV) Size of orbitals increases

A

I, III and IV

B

II, III and IV

C

I and II

D

all are correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the correct statement about the relationship between s-character of hybrid orbitals and various properties, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Understanding s-character and hybridization**: - Hybrid orbitals are formed by the mixing of atomic orbitals. The s-character refers to the proportion of s orbital character in the hybrid orbital. - For example, in sp hybridization, there is 50% s-character and 50% p-character, while in sp3 hybridization, there is 25% s-character and 75% p-character. 2. **Analyzing Option (I): The bond angle decreases**: - As the s-character decreases, the bond angle also decreases. - For example: - sp hybridization has a bond angle of 180°. - sp2 hybridization has a bond angle of 120°. - sp3 hybridization has a bond angle of 109.5°. - Therefore, this statement is **correct**. 3. **Analyzing Option (II): The bond strength increases**: - The bond strength is related to the type of hybridization. - sp hybridized bonds (triple bonds) are stronger than sp2 (double bonds), which are stronger than sp3 (single bonds). - As the s-character decreases, the bond strength actually **decreases**. Thus, this statement is **incorrect**. 4. **Analyzing Option (III): The bond length increases**: - As the s-character decreases, the bond length increases. - This is because sp hybridized bonds are shorter than sp2, which are shorter than sp3. - Therefore, this statement is **correct**. 5. **Analyzing Option (IV): Size of orbitals increases**: - The size of the hybrid orbitals increases as the s-character decreases. - This is because s orbitals are smaller than p orbitals, and thus sp hybrid orbitals are smaller than sp2, which are smaller than sp3. - Therefore, this statement is **correct**. ### Conclusion: Based on the analysis: - Option (I) is correct: The bond angle decreases. - Option (II) is incorrect: The bond strength does not increase. - Option (III) is correct: The bond length increases. - Option (IV) is correct: The size of orbitals increases. Thus, the correct statements are (I), (III), and (IV).
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