The correct statement regarding `SO_(2)` molecule is :

Options

A. two `p pi -d pi `bonds
B. molecule has 2 lone pair, `2sigma` bonds and `2pi` bonds
C. two `p pi-p pi` bonds
D. one `p pi - p pi` and one `p pi - dpi` bond

Answer

To determine the correct statement regarding the SO₂ molecule, we can follow these steps:

### Step 1: Identify the central atom and its valence electrons
- The central atom in SO₂ is sulfur (S).
- Sulfur has 6 valence electrons (from group 16 of the periodic table).

### Step 2: Determine the number of attached atoms
- SO₂ has two oxygen (O) atoms attached to the sulfur atom. Each oxygen is divalent.

### Step 3: Calculate the steric number
- The steric number (SN) can be calculated using the formula:
\[ \text{SN} = \frac{V + M + C}{2} \]
where:
- \( V \) = number of valence electrons of the central atom (6 for S)
- \( M \) = number of monovalent atoms attached (0, since O is divalent)
- \( C \) = charge on the central atom (0 for neutral SO₂)

Thus:
\[ \text{SN} = \frac{6 + 0 + 0}{2} = 3 \]

### Step 4: Determine hybridization
- A steric number of 3 indicates that the hybridization of sulfur in SO₂ is sp².

### Step 5: Identify lone pairs and bond pairs
- With a steric number of 3 and 2 bond pairs (from the two S=O double bonds), there is 1 lone pair on the sulfur atom.

### Step 6: Analyze the bonding in SO₂
- The bonding in SO₂ involves:
- 2 sigma (σ) bonds formed between sulfur and each oxygen.
- 2 pi (π) bonds formed from the overlap of p orbitals from sulfur and oxygen.

### Step 7: Identify the types of bonds
- The bonds can be classified as:
- 1 p-pi-p-pi bond (from the overlap of p orbitals of sulfur and oxygen).
- 1 p-pi-d-pi bond (where one of the pi bonds involves the d orbital of sulfur).

### Step 8: Conclusion
- The correct statement regarding SO₂ is that it has one p-pi-p-pi bond and one p-pi-d-pi bond.

### Final Answer
The correct statement regarding the SO₂ molecule is: **It has one p-pi-p-pi bond and one p-pi-d-pi bond.**

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