Which of the following set of species have planar structure?

Options

A. `I_(3)^(-), CH_(3), Cl_(3)^(-), SiF_(6)^(2-)`
B. `I_(3)^(+), ICl_(4)^(-), Al_(2)Cl_(6), TeCl_(4)`
C. `SCl_(2), N_(2)O_(5), SF_(4)`
D. `I_(2)Cl_(6), XeF_(2), BrF_(4)^(-), XeF_(5)^(-)`

Explanation

To determine which set of species have a planar structure, we need to analyze the molecular geometry of each species in the provided options. Let's go through the options step by step.

### Step 1: Analyze Option A: I3- and I3+
1. **I3-**: The structure is linear due to the presence of lone pairs on the central iodine atom. Therefore, I3- is **not planar**.
2. **I3+**: This species has a linear structure as well, but due to the positive charge, it can adopt a planar configuration. Thus, I3+ is **planar**.

**Conclusion for Option A**: Not all species are planar (I3- is not planar).

### Step 2: Analyze Option B: ICl4- and Al2Cl6
1. **ICl4-**: The structure is square planar due to the presence of two lone pairs on the iodine atom. Thus, ICl4- is **planar**.
2. **Al2Cl6**: The structure is non-planar due to the presence of indirect bonding and steric effects. Therefore, Al2Cl6 is **not planar**.

**Conclusion for Option B**: Not all species are planar (Al2Cl6 is not planar).

### Step 3: Analyze Option C: SCl2, N2O5, and SF4
1. **SCl2**: The structure is bent due to the presence of lone pairs on sulfur, making it **planar**.
2. **N2O5**: The structure is planar due to resonance and the arrangement of nitrogen and oxygen atoms. Thus, N2O5 is **planar**.
3. **SF4**: The structure is non-planar due to the presence of a lone pair on sulfur, which distorts the geometry. Therefore, SF4 is **not planar**.

**Conclusion for Option C**: Not all species are planar (SF4 is not planar).

### Step 4: Analyze Option D: I2Cl6, XeF2, BrF4-, and XeF5-
1. **I2Cl6**: The structure is square planar due to the presence of two lone pairs on one of the iodine atoms. Thus, I2Cl6 is **planar**.
2. **XeF2**: The structure is linear due to three lone pairs on xenon, making it **planar**.
3. **BrF4-**: The structure is square planar due to the presence of two lone pairs on bromine. Thus, BrF4- is **planar**.
4. **XeF5-**: The structure is pentagonal planar due to the presence of one lone pair on xenon. Thus, XeF5- is **planar**.

**Conclusion for Option D**: All species are planar.

### Final Answer:
The correct answer is **Option D** as all species in this set have a planar structure.

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