Which of the following structure(s) is /are non-planar?

Options

A. `Na_(3)B_(3)O_(6)`
B. `I_(2)Cl_(6)`
C. Sheet silicate
D. Inorganic graphite layer

Explanation

To determine which of the given structures are non-planar, we will analyze each structure based on their molecular geometry and hybridization. Here’s a step-by-step breakdown:

### Step 1: Analyze Na3B3O6
1. **Ionization**: The compound Na3B3O6 ionizes to Na3+ and B3O6^3-.
2. **Structure Drawing**: The B3O6^3- anion contains BOO linkages.
3. **Geometry**: The structure is planar as all atoms lie in the same plane with no bonds extending out of the plane.

### Conclusion for Na3B3O6: **Planar**

### Step 2: Analyze I2Cl6
1. **Structure Drawing**: The structure consists of iodine (I) and chlorine (Cl) atoms.
2. **Hybridization**: Iodine has 7 valence electrons and forms bonds with chlorine atoms. The hybridization can be calculated as sp3d2.
3. **Geometry**: The structure is planar because the lone pairs on iodine cancel each other out, keeping the molecule flat.

### Conclusion for I2Cl6: **Planar**

### Step 3: Analyze Silicate
1. **Basic Unit**: Silicates are derived from the tetrahedral unit SiO4^4-.
2. **Tetrahedral Geometry**: The tetrahedral structure has bond angles of 109 degrees, indicating that it is not flat.
3. **Polymeric Form**: When these tetrahedral units form sheets, the overall structure remains non-planar due to the angles between the bonds.

### Conclusion for Silicate: **Non-Planar**

### Step 4: Analyze Inorganic Graphite Layer
1. **Structure Drawing**: The structure consists of boron (B) and nitrogen (N) atoms.
2. **Hybridization**: Both boron and nitrogen are sp2 hybridized, which typically results in planar structures.
3. **Geometry**: The structure extends in a flat plane due to the sp2 hybridization.

### Conclusion for Inorganic Graphite Layer: **Planar**

### Final Summary:
- **Non-Planar Structure**: Silicate
- **Planar Structures**: Na3B3O6, I2Cl6, Inorganic Graphite Layer