If `CdI_(2)` is pink in colour, the `CdCl_(2)` will be '_____' coloured.

Options

A. Yellow
B. Red
C. Blue
D. connot be predicted

Explanation

To solve the question about the color of `CdCl2` given that `CdI2` is pink in color, we can follow these steps:

### Step 1: Understand the Color of `CdI2`
- `CdI2` is pink in color.
- The reason for this color is due to the polarization of the `Cd^2+` ion by the `I^-` ion. The `I^-` ion has a larger size and can effectively polarize the `Cd^2+` ion, leading to the formation of a colored complex.

### Step 2: Identify the Ions in `CdCl2`
- `CdCl2` consists of `Cd^2+` and `Cl^-` ions.
- The `Cl^-` ion is smaller and has a lower polarizing power compared to `I^-`.

### Step 3: Compare Polarization Ability
- The polarization ability of `Cl^-` is less than that of `I^-`. This means that `Cl^-` will not be able to polarize `Cd^2+` as effectively as `I^-` does.
- Since polarization is directly related to the color observed, the reduced polarization will likely result in a different color or no distinct color.

### Step 4: Conclusion on the Color of `CdCl2`
- Given that the polarization from `Cl^-` to `Cd^2+` is less, we cannot predict a specific color for `CdCl2` based on the information provided.
- The color of `CdCl2` cannot be determined without experimental observation.

### Final Answer
- Therefore, the answer to the question is: **cannot be predicted**.

---