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Both N(SiH(3))(3) and NH(SiH(3))(2) comp...

Both `N(SiH_(3))_(3) and NH(SiH_(3))_(2)` compounds have trigonal planar skeleton. Incorrect statement about both compounds is :

A

`SiNSi` bond angle in `NH(SiH_(3))_(2)gtSiNSi` bond angle in `N(SiH_(3))_(3))`

B

`N-Si` bond length in `NH(SiH_(3))_(2)gtN-Si` bond length in `N(SiH_(3))_(3))`

C

`N-Si` bond length in `NH(SiH_(3))_(2)ltN-Si` bond length in `N(SiH_(3))_(3))`

D

Back bonding strength in `NH(SiH_(3))_(2)gt` Back bonding strength in `N(SiH_(3))_(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the compounds \( N(SiH_3)_3 \) and \( NH(SiH_3)_2 \) and identify the incorrect statement about them, we will analyze the structures and bonding characteristics of both compounds step by step. ### Step 1: Understand the Structures 1. **Compound 1: \( N(SiH_3)_3 \)** - This compound has a nitrogen atom bonded to three \( SiH_3 \) groups. - The nitrogen has a lone pair of electrons, which can participate in back bonding with the silicon atoms. - The geometry around the nitrogen is trigonal planar due to the three \( SiH_3 \) groups and the lone pair. 2. **Compound 2: \( NH(SiH_3)_2 \)** - This compound has a nitrogen atom bonded to one hydrogen atom and two \( SiH_3 \) groups. - Similar to the first compound, the nitrogen can also engage in back bonding with the silicon atoms. - The geometry around the nitrogen is also trigonal planar. ### Step 2: Analyze Bonding and Angles - **Back Bonding:** In both compounds, back bonding occurs between the lone pair on nitrogen and the vacant p-orbitals of silicon. This back bonding stabilizes the structure and influences bond angles. - **Bond Angles:** The bond angles in both compounds are expected to be approximately 120 degrees due to the trigonal planar arrangement. ### Step 3: Evaluate the Statements We need to evaluate the statements provided in the question. 1. **Statement A:** The Si-Si bond angle in \( NH(SiH_3)_2 \) is greater than the Si-Si bond angle in \( N(SiH_3)_3 \). - This statement is **correct** because the back bonding in \( NH(SiH_3)_2 \) is distributed among two \( SiH_3 \) groups, leading to stronger bond angles. 2. **Statement B:** The N-Si bond length in \( NH(SiH_3)_2 \) is greater than the N-Si bond length in \( N(SiH_3)_3 \). - This statement is **incorrect**. The bond strength due to back bonding is greater in \( N(SiH_3)_3 \) because the lone pair is shared among three \( SiH_3 \) groups, resulting in a shorter N-Si bond length. 3. **Statement C:** The N-Si bond length in \( N(SiH_3)_3 \) is less than the N-Si bond length in \( NH(SiH_3)_2 \). - This statement is **correct** and aligns with the explanation above. 4. **Statement D:** The back bonding strength in \( NH(SiH_3)_2 \) is greater than in \( N(SiH_3)_3 \). - This statement is **correct** as the back bonding is stronger in \( N(SiH_3)_3 \) due to the involvement of three \( SiH_3 \) groups. ### Conclusion The incorrect statement about both compounds is **Statement B**.

To solve the problem regarding the compounds \( N(SiH_3)_3 \) and \( NH(SiH_3)_2 \) and identify the incorrect statement about them, we will analyze the structures and bonding characteristics of both compounds step by step. ### Step 1: Understand the Structures 1. **Compound 1: \( N(SiH_3)_3 \)** - This compound has a nitrogen atom bonded to three \( SiH_3 \) groups. - The nitrogen has a lone pair of electrons, which can participate in back bonding with the silicon atoms. - The geometry around the nitrogen is trigonal planar due to the three \( SiH_3 \) groups and the lone pair. ...
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