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The incorrect statement regarding O(SiH(...

The incorrect statement regarding `O(SiH_(3))_(2) and OCl_(2)` molecule is/are

A

The strength of back bonding is more in `O(SiH_(3))_(2)` molecule than `Ocl_(2)` molecule

B

`Si-O-Si` bond angle in `O(SiH_(3))_(2)` is greater than `Cl-O-Cl` bond angle in `OCl_(2)`

C

The nature of back in both molecules is `2p_(x)-3d_(pi)`

D

Hybridisation of central O-atom in both molecules is same

Text Solution

AI Generated Solution

The correct Answer is:
To determine the incorrect statement regarding the molecules OSiH₃₂ and OCl₂, we will analyze each option step by step. ### Step 1: Analyze Back Bonding Strength - **Statement**: The strength of back bonding is more in OSiH₃₂ than in OCl₂. - **Analysis**: In OSiH₃₂, the back bonding involves the 2P orbitals of oxygen and the 3D orbitals of silicon, which allows for effective overlap and stronger back bonding. In contrast, OCl₂ has less effective back bonding due to the larger size of chlorine atoms, which do not allow for effective overlap with the oxygen's orbitals. - **Conclusion**: This statement is **correct**. ### Step 2: Compare Bond Angles - **Statement**: The Si-O-Si bond angle in OSiH₃₂ is greater than the Cl-O-Cl bond angle in OCl₂. - **Analysis**: The bond angle in OSiH₃₂ is approximately 144 degrees due to the presence of lone pairs and the hybridization of sp². In OCl₂, the bond angle is around 111 degrees due to sp³ hybridization and the repulsion between lone pairs. - **Conclusion**: This statement is **correct**. ### Step 3: Nature of Back Bonding - **Statement**: The nature of back bonding in both molecules is 2Pₓ 3D π. - **Analysis**: In OSiH₃₂, the back bonding is indeed characterized by 2P and 3D orbitals. However, in OCl₂, the back bonding is less effective and does not involve significant 3D orbital participation. - **Conclusion**: This statement is **correct**. ### Step 4: Hybridization of Central Oxygen Atoms - **Statement**: The hybridization of central O atoms in both molecules is the same. - **Analysis**: In OSiH₃₂, the oxygen atom undergoes sp² hybridization due to the presence of one lone pair and the formation of sigma bonds with silicon. In OCl₂, the oxygen atom is sp³ hybridized due to two lone pairs and two sigma bonds with chlorine. - **Conclusion**: This statement is **incorrect**. ### Final Conclusion The incorrect statement regarding OSiH₃₂ and OCl₂ is the fourth statement: "The hybridization of central O atoms in both molecules is the same." ---

To determine the incorrect statement regarding the molecules OSiH₃₂ and OCl₂, we will analyze each option step by step. ### Step 1: Analyze Back Bonding Strength - **Statement**: The strength of back bonding is more in OSiH₃₂ than in OCl₂. - **Analysis**: In OSiH₃₂, the back bonding involves the 2P orbitals of oxygen and the 3D orbitals of silicon, which allows for effective overlap and stronger back bonding. In contrast, OCl₂ has less effective back bonding due to the larger size of chlorine atoms, which do not allow for effective overlap with the oxygen's orbitals. - **Conclusion**: This statement is **correct**. ### Step 2: Compare Bond Angles ...
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