The geometry with respect ot the central atom of the following molecules are
`N(SiH_(3))_(3), Me_(3)N , (SiH_(3))_(3) P`

Options

A. planar, pyramidal, planar
B. planar, pyramidal, pyramidal
C. pyramidal, pyramidal, pyramidal
D. pyramidal, planar, pyramidal

Explanation

To determine the geometry with respect to the central atom of the molecules \( N(SiH_3)_3 \), \( Me_3N \), and \( (SiH_3)_3P \), we will analyze each molecule step by step.

### Step 1: Analyze \( N(SiH_3)_3 \)

1. **Identify the central atom**: The central atom in this molecule is nitrogen (N).
2. **Count the substituents**: There are three \( SiH_3 \) groups attached to the nitrogen atom.
3. **Consider lone pairs**: Nitrogen has one lone pair of electrons.
4. **Determine hybridization**: The nitrogen atom is surrounded by three \( SiH_3 \) groups and one lone pair. This gives a total of four regions of electron density, which corresponds to \( sp^3 \) hybridization.
5. **Determine geometry**: The presence of one lone pair leads to a trigonal pyramidal geometry.

### Step 2: Analyze \( Me_3N \)

1. **Identify the central atom**: The central atom is again nitrogen (N).
2. **Count the substituents**: There are three methyl (Me) groups attached to the nitrogen atom.
3. **Consider lone pairs**: Nitrogen has one lone pair of electrons.
4. **Determine hybridization**: Similar to the previous molecule, nitrogen is surrounded by three methyl groups and one lone pair, leading to a total of four regions of electron density, which corresponds to \( sp^3 \) hybridization.
5. **Determine geometry**: The presence of one lone pair results in a trigonal pyramidal geometry.

### Step 3: Analyze \( (SiH_3)_3P \)

1. **Identify the central atom**: The central atom in this molecule is phosphorus (P).
2. **Count the substituents**: There are three \( SiH_3 \) groups attached to the phosphorus atom.
3. **Consider lone pairs**: Phosphorus has one lone pair of electrons.
4. **Determine hybridization**: Phosphorus is surrounded by three \( SiH_3 \) groups and one lone pair, leading to a total of four regions of electron density, which corresponds to \( sp^3 \) hybridization.
5. **Determine geometry**: The presence of one lone pair results in a trigonal pyramidal geometry.

### Summary of Geometries

- \( N(SiH_3)_3 \): Trigonal pyramidal
- \( Me_3N \): Trigonal pyramidal
- \( (SiH_3)_3P \): Trigonal pyramidal