Arrange in increasing order of extent of hydrolysis `[C Cl_(4),MgCl_(2),AlCl_(3),PCl_(5),SiCl_(4)]`.

Options

A. `C Cl_(4)ltMgCl_(2)ltAlCl_(3)ltSiCl_(4)ltPCl_(5)`
B. `C Cl_(4)ltAlCl_(3)ltMgCl_(2)ltPCl_(5)ltSiCl_(4)`
C. `C Cl_(4)ltSiCl_(4)ltPCl_(5)ltAlCl_(3)ltMgCl_(2)`
D. `C Cl_(4)ltPCl_(5)ltSiCl_(4)ltAlCl_(3)ltMgCl_(2)`

Explanation

To solve the problem of arranging the compounds \( CCl_4, MgCl_2, AlCl_3, PCl_5, \) and \( SiCl_4 \) in increasing order of their extent of hydrolysis, we can follow these steps:

### Step 1: Understand Hydrolysis
Hydrolysis refers to the reaction of a compound with water, which can lead to the formation of acids or bases. The extent of hydrolysis is influenced by the nature of the central atom and its oxidation state.

### Step 2: Analyze Each Compound
1. **\( CCl_4 \)**: Carbon has no vacant d-orbitals and does not undergo hydrolysis. Therefore, it has the least extent of hydrolysis.
2. **\( MgCl_2 \)**: Magnesium has an oxidation state of +2. It can undergo hydrolysis but to a lesser extent compared to compounds with higher oxidation states.
3. **\( AlCl_3 \)**: Aluminum has an oxidation state of +3. It hydrolyzes more than \( MgCl_2 \) due to its higher oxidation state.
4. **\( SiCl_4 \)**: Silicon has an oxidation state of +4. It has a higher tendency to hydrolyze than both \( MgCl_2 \) and \( AlCl_3 \).
5. **\( PCl_5 \)**: Phosphorus has the highest oxidation state of +5, leading to the greatest extent of hydrolysis.

### Step 3: Determine the Order of Hydrolysis
Based on the analysis:
- \( CCl_4 \) has the least extent of hydrolysis.
- Next is \( MgCl_2 \).
- Followed by \( AlCl_3 \).
- Then \( SiCl_4 \).
- Finally, \( PCl_5 \) has the highest extent of hydrolysis.

### Final Order
Thus, the increasing order of extent of hydrolysis is:
\[ CCl_4 < MgCl_2 < AlCl_3 < SiCl_4 < PCl_5 \]

### Step 4: Write the Answer
The final answer is:
\[ CCl_4, MgCl_2, AlCl_3, SiCl_4, PCl_5 \]