Home
Class 12
CHEMISTRY
Choose incorrect stability order:...

Choose incorrect stability order:

A

`[Cu(NH_(3))_(4)]^(2+) lt [Cu(en)_(2)]^(2+) lt [Cu("trien")]^(2+)`

B

`[Fe(H_(2)O)_(6)]^(3+) lt [Fe(NO_(2))_(6)]^(3-) lt [Fe(NH_(3))_(6)]^(3+)`

C

`[Co(H_(2)O)_(6)]^(3+) lt [Rh(H_(2)O)_(6)]^(3+) lt [Ir(H_(2)O)_(6)]^(3+)`

D

`[Cr(NH_(3))_(6)]^(1+) lt [Cr(NH_(3))_(6)]^(2+) lt [Cr(NH_(3))_(6)]^(3+)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of choosing the incorrect stability order, we will follow a systematic approach based on the strength of ligands and the oxidation states of the central metal atom. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Stability Order The stability of coordination compounds is influenced by: - The nature of the central metal atom (its oxidation state). - The strength of the ligands attached to the metal. ### Step 2: Review the Spectrochemical Series The spectrochemical series ranks ligands based on their field strength: 1. Weak field ligands: Iodide (I⁻), Bromide (Br⁻), Chloride (Cl⁻) 2. Moderate field ligands: Water (H₂O), Hydroxide (OH⁻), Nitrite (NO₂⁻) 3. Strong field ligands: Ammonia (NH₃), Ethylenediamine (en), Cyanide (CN⁻) ### Step 3: Analyze the Given Options We need to evaluate the stability orders provided in the options. The question states that we need to find the incorrect order. #### Option Analysis: 1. **Option 1**: Amine (NH₃) < Ethylenediamine (en) < Tri-N (trien) - This order is correct as ethylenediamine is a stronger ligand than ammonia. 2. **Option 2**: Aqua (H₂O) < Nitrite (NO₂⁻) < Amine (NH₃) - This order is incorrect. According to the spectrochemical series, nitrite (NO₂⁻) is a stronger ligand than ammonia (NH₃). Thus, the correct order should be: Aqua < Nitrite < Amine. 3. **Option 3**: Cobalt (Co) < Rhodium (Rh) < Iridium (Ir) - This order is correct as stability increases down the group due to the involvement of inner d-orbitals. 4. **Option 4**: Chromium oxidation states (Cr²⁺, Cr³⁺, Cr⁶⁺) - This order is also correct as the stability of chromium complexes generally increases with higher oxidation states. ### Step 4: Conclusion From the analysis, the incorrect stability order is found in **Option 2** where it incorrectly states that NO₂⁻ is less stable than NH₃. ### Final Answer The incorrect stability order is: Aqua < Nitrite < Amine (Option 2). ---

To solve the question of choosing the incorrect stability order, we will follow a systematic approach based on the strength of ligands and the oxidation states of the central metal atom. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Stability Order The stability of coordination compounds is influenced by: - The nature of the central metal atom (its oxidation state). - The strength of the ligands attached to the metal. ### Step 2: Review the Spectrochemical Series ...
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise LEVEL 3 (PASSAGE TYPE)|98 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise ONE OR MORE ANSWERS IS/ARE CORRECT|71 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos
  • d-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise ASSERTION-REASON TYPE QUESTIONS|32 Videos

Similar Questions

Explore conceptually related problems

The incorrect stability order of +3 and +1 states of 13th group elements (boron family) is:

Choose incorrect match

The correct stability order for the following species is

The correct stability order for the following species is :

The correct stability order of the given carbanions is

The correct stability order of following species is :

The correct stability order of following species is :

The correct stability order of the following species is

Choose incorrect statement :

VK JAISWAL ENGLISH-CO-ORDINATION COMPOUNDS-LEVEL 2
  1. Choose incorrect stability order:

    Text Solution

    |

  2. Which of the following ligand does not as pi-acid ligand?

    Text Solution

    |

  3. If EAN of central metal cation M^(2+) in an non-chelating complex is 3...

    Text Solution

    |

  4. [Mn(CO)(4)NO] is diamagnetic because:

    Text Solution

    |

  5. Choose the correct option regarding the following complex compound whi...

    Text Solution

    |

  6. If CO ligands are substituted by NO in respective neutral carbonyl com...

    Text Solution

    |

  7. Which of the following species can act as reducing agent ?

    Text Solution

    |

  8. If Delta(0) lt P, the correct electronic configuration for d^(4) syste...

    Text Solution

    |

  9. Which of the following statement is not correct?

    Text Solution

    |

  10. Give the correct of initials T or F for following statements. Use T if...

    Text Solution

    |

  11. match List-I with list-II and select the correct answer using the code...

    Text Solution

    |

  12. The value of 'spin only' magnetic moment for one of the following conf...

    Text Solution

    |

  13. The correct order of magnetic moments (spin values in B.M.) among is:

    Text Solution

    |

  14. Which of the following statements is incorrect?

    Text Solution

    |

  15. Set of d-orbitals which is used by central metal during formation of M...

    Text Solution

    |

  16. FeSO(4) is a very good absorber for NO, the new compound formed by thi...

    Text Solution

    |

  17. A [M(H(2)O)(6)]^(2+) complex typically absorbs at around 600 n. it is ...

    Text Solution

    |

  18. Given that the energy of the photons of different colours decreases in...

    Text Solution

    |

  19. The CFSE for octahedral [CoCl(6)]^(4-) is 18,000 cm^(-1) . The CFSE fo...

    Text Solution

    |

  20. MnO(4)^(-) is of intense pink colour, though Mn is in(+7) oxidation st...

    Text Solution

    |

  21. In which of the following complex ion the value of magnetic moment (sp...

    Text Solution

    |