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An aqueous solution of titanium bromide ...

An aqueous solution of titanium bromide shows zero magnetic moment. Assuming the complex as octahedral in aqueous solution, the formula of the complex is .

A

`[Ti(H_(2)O)_(6)]Cl_(2)`

B

`[Ti(H_(2)O)_(6)]Cl_(4)`

C

`[TiCl_(3)(H_(2)O)_(3)]`

D

`[TiCl_(2)(H_(2)O)_(4)]`

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The correct Answer is:
To solve the problem, we need to determine the formula of the titanium bromide complex that shows zero magnetic moment in an aqueous solution, assuming it has an octahedral geometry. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the oxidation states of titanium in the complex 1. **Understanding the charge of titanium bromide**: Titanium (Ti) can exist in multiple oxidation states, commonly +2, +3, and +4. 2. **Assuming the complex is octahedral**: In an octahedral complex, the coordination number is 6. The complex can be represented as Ti(H2O)6^x, where x is the oxidation state of titanium. 3. **Considering the bromide ions**: Since bromide (Br) is a monovalent anion (charge -1), the overall charge of the complex will depend on the number of bromide ions present. ### Step 2: Determine the possible complexes 1. **Possible complexes**: - TiBr2(H2O)4 - TiBr3(H2O)3 - TiBr4(H2O)2 - TiBr5(H2O)1 2. **Calculate oxidation states**: - For TiBr2(H2O)4: - Charge = 2(-1) + x + 0 = 0 → x = +2 - For TiBr3(H2O)3: - Charge = 3(-1) + x + 0 = 0 → x = +3 - For TiBr4(H2O)2: - Charge = 4(-1) + x + 0 = 0 → x = +4 - For TiBr5(H2O)1: - Charge = 5(-1) + x + 0 = 0 → x = +5 (not possible for Ti) ### Step 3: Analyze the magnetic properties 1. **Understanding magnetic moment**: A zero magnetic moment indicates that the complex is diamagnetic, meaning it has no unpaired electrons. 2. **Electronic configuration of titanium**: - Ti (atomic number 22) has the electronic configuration: [Ar] 4s² 3d². - For Ti²⁺: [Ar] 3d² (2 unpaired electrons) - paramagnetic. - For Ti³⁺: [Ar] 3d¹ (1 unpaired electron) - paramagnetic. - For Ti⁴⁺: [Ar] 3d⁰ (no unpaired electrons) - diamagnetic. ### Step 4: Conclusion - The complex that shows zero magnetic moment must have titanium in the +4 oxidation state (Ti⁴⁺) since it is diamagnetic. - The formula of the complex is **TiBr4(H2O)2** because it contains 4 bromide ions and 2 water molecules, leading to a +4 oxidation state for titanium. ### Final Answer The formula of the complex is **TiBr4(H2O)2**. ---

To solve the problem, we need to determine the formula of the titanium bromide complex that shows zero magnetic moment in an aqueous solution, assuming it has an octahedral geometry. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the oxidation states of titanium in the complex 1. **Understanding the charge of titanium bromide**: Titanium (Ti) can exist in multiple oxidation states, commonly +2, +3, and +4. 2. **Assuming the complex is octahedral**: In an octahedral complex, the coordination number is 6. The complex can be represented as Ti(H2O)6^x, where x is the oxidation state of titanium. 3. **Considering the bromide ions**: Since bromide (Br) is a monovalent anion (charge -1), the overall charge of the complex will depend on the number of bromide ions present. ### Step 2: Determine the possible complexes ...
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