Which one of the following pairs of isomers ad ytpes of isomerism are correctly mathced?
(i) [`Co(NH_(3))_(5)(NO_(2))]Cl_(2) and [Co(NH_(3))_(5)(ONO)]Cl_(2)` . . . (Linkage)
(ii) `[Cu(NH_(3))_(4)][PtCl_(4)] and [Pt(NH_(3))_(4)][CuCl_(4)]` . .. (coordination)
(iii) `[PtCl_(2)(NH_(3))_(4)]Br_(2) and [PtBr_(2)(NH_(3))_(4)]Cl_(2)` . . (Ionization)
Select the correct answer using the codes given below:

Options

A. (ii) and (iii)
B. (i), (ii) and (iii)
C. (i) and (iii)
D. (i) and (ii)

Answer

To solve the problem, we need to analyze each pair of isomers and determine if the types of isomerism they represent are correctly matched.

### Step-by-Step Solution:

1. **Identify the first pair of isomers:**
- The first pair is `[Co(NH₃)₅(NO₂)]Cl₂` and `[Co(NH₃)₅(ONO)]Cl₂`.
- Here, we have a nitro ligand (NO₂) that can coordinate through either nitrogen or oxygen. This leads to the formation of two different isomers based on which atom is donating the lone pair.
- **Type of isomerism:** Linkage isomerism (correctly matched).

2. **Identify the second pair of isomers:**
- The second pair is `[Cu(NH₃)₄][PtCl₄]` and `[Pt(NH₃)₄][CuCl₄]`.
- In this case, the isomers differ in the distribution of ligands between the two metal centers (copper and platinum). This means that the ligands are distributed differently around the central metal atoms.
- **Type of isomerism:** Coordination isomerism (correctly matched).

3. **Identify the third pair of isomers:**
- The third pair is `[PtCl₂(NH₃)₄]Br₂` and `[PtBr₂(NH₃)₄]Cl₂`.
- Here, the isomers differ in the anionic species that are outside the coordination sphere. One has bromide ions outside while the other has chloride ions outside.
- **Type of isomerism:** Ionization isomerism (correctly matched).

### Conclusion:
All three pairs of isomers are correctly matched with their respective types of isomerism. Therefore, the correct answer is that all options are correct.

### Final Answer:
All pairs are correctly matched: (i) Linkage, (ii) Coordination, (iii) Ionization.