[Mn(CO)(4)NO] is diamagnetic because:...

`[Mn(CO)_(4)NO]` is diamagnetic because:

Mn metal is diamagnetiic in free state

Mn is in +1 oxidation state in this complex

No is present as positive ligand

All of these

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The correct Answer is:

`[overset(+1)(Mn)(CO)_(4)(NO^(-))]`: Paramagnetic due to presence of unpaired `e^(-)` s in `NO^(-)`
`[overset(-1)(Mn)(CO)_(4)(NO^(+))]:`No unpaired `e^(-)` either on ligands or on `overset(-1)(Mn)` hence it is diamagnetic.

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