Give the correct of initials T or F for following statements. Use T if statements is true and F if it is false.
(I) Co(III) is stabilised in presence of weak field ligands, while Co(II) is stabilised in presence of strong field ligand.
((II) Four coordinated complexes of Pd(II) and Pt(II) are diamagnetic and square planar.
(III) `[Ni(CN)_(4)]^(4-)` ion and `[Ni(CO)_(4)]` are diamagnetic tetrahedral and square planar respectively.
(IV) `Ni^(2+)` ion does not form inner orbital octahedral complexes

Options

A. TFTF
B. TTTF
C. TTFT
D. FTFT

Explanation

To solve the question, we will analyze each statement one by one and determine whether they are true (T) or false (F).

### Step 1: Analyze Statement I
**Statement I**: Co(III) is stabilized in the presence of weak field ligands, while Co(II) is stabilized in the presence of strong field ligands.

- **Analysis**: Cobalt(III) (Co(III)) typically requires strong field ligands to stabilize it due to its higher oxidation state, which leads to a greater tendency for electron pairing. Cobalt(II) (Co(II)), on the other hand, is also stabilized in the presence of strong field ligands. Therefore, this statement is **False (F)**.

### Step 2: Analyze Statement II
**Statement II**: Four coordinated complexes of Pd(II) and Pt(II) are diamagnetic and square planar.

- **Analysis**: Both palladium(II) (Pd(II)) and platinum(II) (Pt(II)) commonly form square planar complexes that are diamagnetic due to the pairing of electrons in their d-orbitals. Therefore, this statement is **True (T)**.

### Step 3: Analyze Statement III
**Statement III**: [Ni(CN)₄]⁴⁻ ion and [Ni(CO)₄] are diamagnetic tetrahedral and square planar respectively.

- **Analysis**: The complex [Ni(CN)₄]⁴⁻ is indeed a strong field ligand complex, leading to electron pairing, and it forms a square planar geometry. However, [Ni(CO)₄] is a tetrahedral complex, not square planar. Therefore, this statement is **False (F)**.

### Step 4: Analyze Statement IV
**Statement IV**: Ni²⁺ ion does not form inner orbital octahedral complexes.

- **Analysis**: The Ni²⁺ ion can form inner orbital complexes when strong field ligands are present, leading to the pairing of electrons and the utilization of the 3d orbitals for bonding. Therefore, this statement is **False (F)**.

### Final Answers
Based on the analysis, we can summarize the answers as follows:
- (I) F
- (II) T
- (III) F
- (IV) F

Thus, the final answer is: **F, T, F, F**.