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MnO(4)^(-) is of intense pink colour, th...

`MnO_(4)^(-)` is of intense pink colour, though `Mn` is in`(+7)` oxidation state.It is due to:

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To understand why the permanganate ion \( \text{MnO}_4^{-} \) is of intense pink color despite manganese being in the +7 oxidation state, we can break down the explanation into several steps: ### Step 1: Identify the oxidation state of manganese in \( \text{MnO}_4^{-} \) In the permanganate ion \( \text{MnO}_4^{-} \), manganese (Mn) is in the +7 oxidation state. This can be determined from the overall charge of the ion and the known oxidation states of oxygen, which is typically -2. ### Step 2: Determine the electronic configuration of \( \text{Mn}^{+7} \) The electronic configuration of manganese in the +7 oxidation state is \( \text{[Ar]} 3d^0 \). This indicates that there are no electrons in the 3d subshell, meaning there are no unpaired electrons. ### Step 3: Understand the implications of having no unpaired electrons Since \( \text{Mn}^{+7} \) has no unpaired electrons, it cannot undergo d-d transitions, which are typically responsible for the absorption of visible light and the appearance of color in transition metal complexes. ### Step 4: Explore the concept of charge transfer Although \( \text{Mn}^{+7} \) has no unpaired electrons, the intense pink color of \( \text{MnO}_4^{-} \) arises from a phenomenon known as charge transfer. In this case, oxygen donates an electron to manganese, effectively reducing it from \( \text{Mn}^{+7} \) to \( \text{Mn}^{+6} \). ### Step 5: Identify the electronic configuration of \( \text{Mn}^{+6} \) The electronic configuration of \( \text{Mn}^{+6} \) is \( \text{[Ar]} 3d^5 \). In this state, there is one unpaired electron in the 3d subshell. ### Step 6: Relate the presence of unpaired electrons to color The presence of one unpaired electron in \( \text{Mn}^{+6} \) allows for d-d transitions, which can absorb certain wavelengths of light. This absorption results in the intense pink color observed in the permanganate ion. ### Conclusion The intense pink color of \( \text{MnO}_4^{-} \) is due to charge transfer from oxygen to manganese, leading to the formation of \( \text{Mn}^{+6} \), which has unpaired electrons that can participate in electronic transitions.
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Transition metals usually from coloured complexes and d-d transitions (t_(2g)hArre_(g)) are responsible for colour as the energy difference between t_(2g) and e_(g) lies in visible region. But all the coloured ions are not dut to d-d transition but charge transfer bands also play important roles. Charge transfer bands may be of two types. (i) ligand to metal (CTLM) " "(ii) metal to ligand (CTML). Charge transfer transition always produces intense colour as compared to d-d transition. MnO_(4)^(-) is dark purple coloured though Mn is in (+VII) oxidation state with 3d^(@) configuration

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