Home
Class 12
CHEMISTRY
The crystal field theory assumes interac...

The crystal field theory assumes interaction between metal ion and the ligands as a purely electrostatic and ligands are supposed to be point charges.
Q. Amongst the following complexes which has square planar geometry?

A

`[RhCl(CO)(P Ph_(3))_(2)]`

B

`K_(2)[Cu(SCN)_(4)]`

C

`K_(2)[Ni(PPH_(3))_(2)Cl_(2)]`

D

`MnO_(4)^(2-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the following complexes has a square planar geometry, we will analyze the options provided based on the principles of crystal field theory and the characteristics of transition metals. ### Step-by-Step Solution: 1. **Understanding Square Planar Geometry**: - Square planar geometry is typically observed in certain transition metal complexes, particularly those involving d8 metal ions. The geometry arises due to the specific arrangement of ligands around the central metal ion, which minimizes electron repulsion and stabilizes the complex. 2. **Identifying Transition Metals**: - We need to identify the transition metals in the given complexes. Transition metals are typically found in groups 3 to 12 of the periodic table and have partially filled d-orbitals. 3. **Analyzing the Options**: - Let's consider the common transition metals that can form square planar complexes: - **Nickel (Ni)**, **Palladium (Pd)**, **Platinum (Pt)**, and **Rhodium (Rh)** are known to form square planar complexes, particularly in their +2 or +4 oxidation states. - **Copper (Cu)** can also form square planar complexes, especially in the +2 oxidation state. 4. **Evaluating Each Complex**: - For each complex, we need to check the oxidation state of the metal and its electron configuration: - **Rhodium (Rh)**: In the +2 oxidation state, Rh has a d8 configuration, which is conducive to square planar geometry. - **Copper (Cu)**: In the +2 oxidation state, Cu also has a d9 configuration, which can lead to square planar complexes but is less stable compared to d8. - **Nickel (Ni)**: In the +2 oxidation state, Ni has a d8 configuration, which can also form square planar complexes. - **Manganese (Mn)**: Typically does not form square planar complexes in its common oxidation states. 5. **Conclusion**: - Among the options, **Rhodium (Rh)** is the most stable square planar complex due to its d8 configuration and its position in the second transition series, which allows for stronger ligand interactions and stabilization of the square planar geometry. ### Final Answer: The complex that has square planar geometry is **Rhodium complex**.
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise ONE OR MORE ANSWERS IS/ARE CORRECT|71 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise MATCH THE COLUMN|36 Videos
  • CO-ORDINATION COMPOUNDS

    VK JAISWAL ENGLISH|Exercise LEVEL 2|144 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos
  • d-BLOCK ELEMENTS

    VK JAISWAL ENGLISH|Exercise ASSERTION-REASON TYPE QUESTIONS|32 Videos

Similar Questions

Explore conceptually related problems

The crystal field theory assumes interaction between metal ion and the ligands as a purely electrostatic and ligands are supposed to be point charges. Q. Which of the following match are incorrect?

The crystal field theory assumes interaction between metal ion and the ligands as a purely electrostatic and ligands are supposed to be point charges. Q. Which of the following order of CFSE in incorrect?

Square planar complexes are formed by d^(8) ions with strong field ligands The crystal field splitting Delta_(0) is larger for the second and theird row transition elements and for more highly charged species All the complexes having 4d^(8) and 5d^(8) configurations are mostly square planar including those with weak field ligands such as halide ions square planar complexes can show geometrical isomerism but they do not show optical isomerism due to the presence of plane of symmetry Among the following complexes which has a square planar geometry? (a) [RhCl(CO)(PPh_(3))_(2)] (b) K_(3)[Cu(CN)_(4)] (c ) [Ni(CO)_(4)] (d) K_(2)[Zn(CN)_(4)] .

According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. ltBrgt Q. Correct relationship between pairing energy (P) and C.F.S.E. (Delta_(o)) in

According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. ltBrgt Q. The crystal field-spliting order for Cr^(3+) cation is octahedral field for ligands CH_(3)COO^(-),NH_(3),H_(2)O,CN^(-) is:

According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. Q. The crystal field-spliting order for Cr^(3+) cation is octahedral field for ligands CH_(3)COO^(-),NH_(3),H_(2)O,CN^(-) is:

According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. ltBrgt Q. The value of 'x' in the complex H_(x)[Co(CO)_(4)] (on the basis of EAN rule), and geometry arround Co ion respectively is:

Crystal field theory provides correct electronic distribution of central metal under surrounding ligannd field, hence it clearly explains magnetic moment, colour of a complex. Q. Which of the following complex is high spin?

Crystal field theory provides correct electronic distribution of central metal under surrounding ligannd field, hence it clearly explains magnetic moment, colour of a complex. Q. In which of the following complex transition of electron occurs from one shell to other shell of central metal.

Crystal field theory provides correct electronic distribution of central metal under surrounding ligannd field, hence it clearly explains magnetic moment, colour of a complex. Q. Which of the following hydrated complex ion has high intensity colour in aqueous solution.

VK JAISWAL ENGLISH-CO-ORDINATION COMPOUNDS-LEVEL 3 (PASSAGE TYPE)
  1. The crystal field theory assumes interaction between metal ion and the...

    Text Solution

    |

  2. The crystal field theory assumes interaction between metal ion and the...

    Text Solution

    |

  3. The crystal field theory assumes interaction between metal ion and the...

    Text Solution

    |

  4. The magnetic property, dipole moment, plane of symmetry, colour and ab...

    Text Solution

    |

  5. The magnetic property, dipole moment, plane of symmetry, colour and ab...

    Text Solution

    |

  6. The magnetic property, dipole moment, plane of symmetry, colour and ab...

    Text Solution

    |

  7. Ligands are broadly classified into two classes classical and non-clas...

    Text Solution

    |

  8. Ligands are broadly classified into two classes classical and non-clas...

    Text Solution

    |

  9. Ligands are broadly classified into two classes classical and non-clas...

    Text Solution

    |

  10. An isomerr of the complex CoBrCl(2)(en)(2)(H(2)O), on reaction with co...

    Text Solution

    |

  11. An isomerr of the complex CoBrCl(2)(en)(2)(H(2)O), on reaction with co...

    Text Solution

    |

  12. Crystal field theory provides correct electronic distribution of centr...

    Text Solution

    |

  13. Crystal field theory provides correct electronic distribution of centr...

    Text Solution

    |

  14. Crystal field theory provides correct electronic distribution of centr...

    Text Solution

    |

  15. Two important physical evidence support the synergic bonding in non-cl...

    Text Solution

    |

  16. Two important physical evidences supporting the synergic bonding in no...

    Text Solution

    |

  17. Two important physical evidences supporting the synergic bonding in no...

    Text Solution

    |

  18. Complex compounds that have the same molecular formula but have differ...

    Text Solution

    |

  19. Complex compounds that have the same molecular formula but have differ...

    Text Solution

    |

  20. Complex compounds that have the same molecular formula but have differ...

    Text Solution

    |