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An isomer of the complex Co(en)(2)(H(2)O...

An isomer of the complex `Co(en)_(2)(H_(2)O)IC l_(2)`, on reaction with concentrated `H_(2)SO_(4)`, it suffers loss in weight and on reaction with `AgNO_(3)` solution gives a yellow precipitated which is isoluble in `NH_(3)` solution.
Q. Total number of space isomers of the formula of the above complex is:

A

2

B

3

C

4

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the total number of space isomers of the complex \( \text{Co(en)}_2(\text{H}_2\text{O})\text{ICl}_2 \), we can follow these steps: ### Step 1: Identify the ligands and coordination sphere The complex consists of cobalt (Co) as the central metal ion, ethylenediamine (en) as a bidentate ligand, water (H2O) as a monodentate ligand, and two chloride ions (Cl) as monodentate ligands. ### Step 2: Determine the coordination number and geometry Cobalt typically has a coordination number of 6 in octahedral complexes. In this case, we have: - 2 ethylenediamine ligands (each bidentate contributes 2) - 1 water molecule (monodentate) - 2 chloride ions (monodentate) This gives a total of 6 coordination sites filled. ### Step 3: Analyze isomerism Space isomers include both geometric (cis/trans) and optical isomers. #### Geometric Isomers: 1. **Cis Isomer**: In this arrangement, the two chloride ions are adjacent to each other. 2. **Trans Isomer**: Here, the two chloride ions are opposite each other. #### Optical Isomers: - The cis isomer can exhibit optical isomerism because it lacks a plane of symmetry, resulting in non-superimposable mirror images. - The trans isomer does not exhibit optical isomerism because it has a plane of symmetry. ### Step 4: Count the isomers - **Cis Isomer**: 1 (with optical isomers) - **Trans Isomer**: 1 (no optical isomers) Thus, the total number of space isomers is: - 1 (cis) + 1 (trans) + 1 (optical from cis) = 3 isomers. ### Final Answer The total number of space isomers of the complex \( \text{Co(en)}_2(\text{H}_2\text{O})\text{ICl}_2 \) is **3**.
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