How many more co-ordination isomers are possible of the compound `[Cu(NH_(3))_(4)][PtCl_(4)]` ?

Answer

To determine how many more coordination isomers are possible for the compound \([Cu(NH_3)_4][PtCl_4]\), we can follow these steps:

### Step 1: Identify the Coordination Spheres
The compound consists of two coordination spheres:
1. The copper(II) complex: \([Cu(NH_3)_4]^{2+}\)
2. The platinum(IV) complex: \([PtCl_4]^{2-}\)

### Step 2: Analyze Possible Isomers
Coordination isomers occur when the ligands can be rearranged between the two metal centers. Here, we can transfer ligands (NH3 and Cl) between the copper and platinum complexes.

### Step 3: List Possible Isomers
1. **First Isomer**: Transfer one Cl from Pt to Cu and one NH3 from Cu to Pt:
- \([Cu(NH_3)_3Cl][PtCl_3(NH_3)]\)

2. **Second Isomer**: Transfer two Cl from Pt to Cu and two NH3 from Cu to Pt:
- \([Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2]\)

3. **Third Isomer**: Transfer three Cl from Pt to Cu and one NH3 from Cu to Pt:
- \([Cu(NH_3)Cl_3][PtCl(NH_3)_3]\)

4. **Fourth Isomer**: Transfer all four Cl from Pt to Cu and all four NH3 from Cu to Pt:
- \([CuCl_4][Pt(NH_3)_4]\)

### Step 4: Count the Isomers
From the analysis, we have identified 4 coordination isomers that can be formed by rearranging the ligands between the two metal centers.

### Conclusion
Thus, the total number of coordination isomers possible for the compound \([Cu(NH_3)_4][PtCl_4]\) is **4**.

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