`FeCr_(2)O_(4)+NaOH+"air" to (A)+Fe_(2)O_(3)`
`(A)+(B) to Na_(2)Cr_(2)O_(7)`
`Na_(2)Cr_(2)O_(7)+X overset(Delta)to Cr_(2)O_(3)`
`Cr_(2)O_(3)+Y overset(Delta)to Cr`
(X) and (Y) are :

Options

A. C and Al
B. Al and C
C. C in both
D. Al in both

Answer

To solve the given problem step by step, we will analyze the reactions and identify the compounds involved.

### Step 1: Identify the reaction of FeCr₂O₄ with NaOH and air
The first reaction involves FeCr₂O₄ (chromite) reacting with NaOH in the presence of air. This reaction leads to the formation of sodium chromate (Na₂CrO₄) and iron(III) oxide (Fe₂O₃).

**Reaction:**
\[ \text{FeCr}_2\text{O}_4 + \text{NaOH} + \text{air} \rightarrow \text{Na}_2\text{CrO}_4 + \text{Fe}_2\text{O}_3 \]

**Hint:** Look for the oxidation states of chromium and iron in the products to confirm the formation of Na₂CrO₄ and Fe₂O₃.

### Step 2: Identify compound (A) and (B)
From the above reaction, we can identify:
- (A) = Na₂CrO₄
- (B) = Fe₂O₃

### Step 3: Reaction of (A) and (B) to form Na₂Cr₂O₇
Next, we combine (A) with (B) to form sodium dichromate (Na₂Cr₂O₇). The reaction typically involves the addition of sulfuric acid (H₂SO₄) to sodium chromate.

**Reaction:**
\[ \text{Na}_2\text{CrO}_4 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{O} \]

**Hint:** Consider the role of sulfuric acid in converting chromate to dichromate.

### Step 4: Identify (X) in the reaction of Na₂Cr₂O₇ to Cr₂O₃
In the next step, Na₂Cr₂O₇ reacts with a reducing agent (X) to produce chromium(III) oxide (Cr₂O₃). A common reducing agent used in this context is carbon (C).

**Reaction:**
\[ \text{Na}_2\text{Cr}_2\text{O}_7 + \text{C} \overset{\Delta}{\rightarrow} \text{Cr}_2\text{O}_3 + \text{Na}_2\text{O} + \text{CO}_2 \]

**Hint:** Look for a reducing agent that can convert Cr from +6 to +3 oxidation state.

### Step 5: Identify (Y) in the reaction of Cr₂O₃ to Cr
Finally, Cr₂O₃ can be reduced to chromium (Cr) using aluminum (Al) as a reducing agent.

**Reaction:**
\[ \text{Cr}_2\text{O}_3 + \text{Al} \overset{\Delta}{\rightarrow} \text{Cr} + \text{Al}_2\text{O}_3 \]

**Hint:** Think about the thermodynamic feasibility of reducing Cr₂O₃ with a metal.

### Conclusion
Based on the above reactions, we can conclude:
- (X) = Carbon (C)
- (Y) = Aluminum (Al)

Thus, the final answer is:
- (X) = Carbon
- (Y) = Aluminum