On heating sodium metal in a current of dry ammonia, the compound formed is
A
sodium imide
B
sodium nitride
C
sodium amide
D
sodium azide
Text Solution
AI Generated Solution
The correct Answer is:
To solve the question regarding the compound formed when sodium metal is heated in a current of dry ammonia, we can follow these steps:
### Step-by-Step Solution:
1. **Understanding the Reactants**:
- We have sodium metal (Na) and dry ammonia (NH3) as the reactants.
2. **Identifying the Reaction**:
- When sodium metal reacts with ammonia, it can lead to the formation of sodium amide (NaNH2) and hydrogen gas (H2).
3. **Writing the Balanced Chemical Equation**:
- The reaction can be represented as:
\[
2 \text{Na} + 2 \text{NH}_3 \rightarrow 2 \text{NaNH}_2 + \text{H}_2
\]
- This equation shows that two moles of sodium react with two moles of ammonia to produce two moles of sodium amide and one mole of hydrogen gas.
4. **Identifying the Product**:
- From the balanced equation, we can see that the primary product formed is sodium amide (NaNH2).
5. **Conclusion**:
- Therefore, the compound formed when sodium metal is heated in a current of dry ammonia is sodium amide.
### Final Answer:
The compound formed is **Sodium Amide (NaNH2)**.
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