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Nitrogen dioxide can not be obtained fro...

Nitrogen dioxide can not be obtained from

A

`Cu(NO_(3))_(2)`

B

`Hg(NO_(3))_(2)`

C

`NaNO_(3)`

D

`AgNO_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which reactant does not produce nitrogen dioxide (NO2), we will analyze the decomposition reactions of each compound mentioned in the question. ### Step-by-Step Solution: 1. **Analyze Copper Nitrate (Cu(NO3)2)**: - When copper nitrate is heated, it decomposes according to the reaction: \[ \text{Cu(NO}_3\text{)}_2 \rightarrow \text{CuO} + 2\text{NO}_2 + \frac{1}{2}\text{O}_2 \] - **Conclusion**: Copper nitrate produces nitrogen dioxide (NO2). 2. **Analyze Mercuric Nitrate (Hg(NO3)2)**: - When mercuric nitrate is heated, it decomposes as follows: \[ \text{Hg(NO}_3\text{)}_2 \rightarrow \text{Hg} + 2\text{NO}_2 + \text{O}_2 \] - **Conclusion**: Mercuric nitrate also produces nitrogen dioxide (NO2). 3. **Analyze Sodium Nitrate (NaNO3)**: - When sodium nitrate is heated, it decomposes to form: \[ 2\text{NaNO}_3 \rightarrow 2\text{NaNO}_2 + \frac{1}{2}\text{O}_2 \] - **Conclusion**: Sodium nitrate does not produce nitrogen dioxide (NO2). 4. **Analyze Silver Nitrate (AgNO3)**: - When silver nitrate is heated, it decomposes according to the reaction: \[ 2\text{AgNO}_3 \rightarrow 2\text{Ag} + 2\text{NO}_2 + \text{O}_2 \] - **Conclusion**: Silver nitrate produces nitrogen dioxide (NO2). ### Final Conclusion: Among the four compounds analyzed, only sodium nitrate does not yield nitrogen dioxide as a product upon decomposition. Therefore, the answer is: **Sodium Nitrate (NaNO3)** cannot be obtained from nitrogen dioxide. ---

To determine which reactant does not produce nitrogen dioxide (NO2), we will analyze the decomposition reactions of each compound mentioned in the question. ### Step-by-Step Solution: 1. **Analyze Copper Nitrate (Cu(NO3)2)**: - When copper nitrate is heated, it decomposes according to the reaction: \[ \text{Cu(NO}_3\text{)}_2 \rightarrow \text{CuO} + 2\text{NO}_2 + \frac{1}{2}\text{O}_2 ...
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