`Naoverset(H_(2)O)(to)Aoverset(CO_(2))(to)Boverset(SO_(2))(to)Coverset(Na_(2)S"/"I_(2))underset(delta)(to)Doverset(Ag^(+)"/"Salt)(to)E`(complex)
Q. The compounds B and C is

Options

A. `Na_(2)CO_(3), Na_(2)SO_(4)`
B. `NaHCO_(3), Na_(2)SO_(4)`
C. `Na_(2)CO_(3), Na_(2)SO_(3)`
D. None of these

Answer

To solve the problem step by step, we will analyze the reactions mentioned in the question and identify the compounds B and C.

### Step 1: Identify Compound A
- **Reaction**: Sodium (Na) reacts with water (H₂O).
- **Product**: Sodium hydroxide (NaOH).
- **Conclusion**: Compound A is NaOH.

**Hint**: Remember that sodium reacts with water to produce sodium hydroxide and hydrogen gas.

### Step 2: Identify Compound B
- **Reaction**: Compound A (NaOH) reacts with carbon dioxide (CO₂).
- **Product**: Sodium carbonate (Na₂CO₃).
- **Conclusion**: Compound B is Na₂CO₃.

**Hint**: When sodium hydroxide reacts with carbon dioxide, it forms a carbonate salt.

### Step 3: Identify Compound C
- **Reaction**: Compound B (Na₂CO₃) reacts with sulfur dioxide (SO₂).
- **Product**: Sodium sulfite (Na₂SO₃).
- **Conclusion**: Compound C is Na₂SO₃.

**Hint**: Sulfur dioxide can react with carbonates to form sulfites.

### Final Answer
- **Compound B**: Na₂CO₃ (sodium carbonate)
- **Compound C**: Na₂SO₃ (sodium sulfite)

### Summary
- The compounds B and C are:
- **B**: Sodium carbonate (Na₂CO₃)
- **C**: Sodium sulfite (Na₂SO₃)