Sodium sulphite `(Na_(2)SO_(3))` is added to meat as a preservative. The presence of `Na_(2)SO_(4)` can be detected by adding dil. `H_(2)SO_(4)` when the pungent smelling gas evolved turns the lime water milky. The gas evolved was detected as sulphur dioxide. The `SO_(2) " to "SO_(4)^(2-)` in titration.
`SO_(2)+2H_(2)O+I_(2) to 4H^(+)+SO_(4)^(2-)+2I^(-)`
In order to check the results of titration, excess barium chloride is added to the final solution. The resulting precipitate is collected and weighed.
Q. Which of the following compounds is formed, when `Na_(2)SO_(3)` is boiled with sulphur.

Options

A. `Na_(2)SO_(4)`
B. `Na_(2)S_(4)O_(5)`
C. `Na_(2)S_(4)O_(6)`
D. `Na_(2)S_(4)O_(3)`

Answer

To determine the compound formed when sodium sulfite `(Na2SO3)` is boiled with sulfur, we can follow these steps:

### Step 1: Understand the Reactants
- We have sodium sulfite `(Na2SO3)` and sulfur `(S)` as reactants.

### Step 2: Identify the Reaction
- When sodium sulfite is boiled with sulfur, a chemical reaction occurs. Sodium sulfite can react with sulfur to form sodium thiosulfate.

### Step 3: Write the Chemical Equation
- The reaction can be represented as:
\[ Na2SO3 + S \rightarrow Na2S2O3 \]
- This indicates that sodium sulfite reacts with sulfur to produce sodium thiosulfate `(Na2S2O3)`.

### Step 4: Conclusion
- Therefore, the compound formed when sodium sulfite is boiled with sulfur is sodium thiosulfate `(Na2S2O3)`.

### Final Answer
- The correct compound formed is **sodium thiosulfate `(Na2S2O3)`**.

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