`2Na[Al(OH)_(4)]+CO_(2)to2Al(OH)_(3)darr+Na_(2)CO_(3)`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To analyze the given reaction and determine the type of reaction it represents, we can follow these steps:

### Step 1: Write the Reaction
The reaction given is:
\[ 2Na[Al(OH)_{4}] + CO_{2} \rightarrow 2Al(OH)_{3} + Na_{2}CO_{3} \]

### Step 2: Identify the Reactants and Products
- **Reactants**:
- Sodium tetrahydroxoaluminate (Na[Al(OH)₄])
- Carbon dioxide (CO₂)

- **Products**:
- Aluminum hydroxide (Al(OH)₃)
- Sodium carbonate (Na₂CO₃)

### Step 3: Check for Solubility
- Sodium tetrahydroxoaluminate is soluble in water.
- Carbon dioxide is a gas and can dissolve in water.
- Aluminum hydroxide (Al(OH)₃) is generally insoluble in water, and it precipitates out of the solution.
- Sodium carbonate (Na₂CO₃) is soluble in water.

### Step 4: Determine the Type of Reaction
In this reaction, we observe that:
- A precipitate (Al(OH)₃) is formed from the reactants.
- The formation of a solid from soluble reactants indicates that this is a **precipitate formation reaction**.

### Conclusion
Thus, the reaction is classified as a **precipitate formation reaction**.

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