`Fe(OH)_(3)darr+NaOH(excess)to`No reaction

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the question regarding the reaction between Fe(OH)₃ and excess NaOH, we need to analyze the situation step by step.

### Step 1: Identify the Reactants
The reactants in this case are:
- **Fe(OH)₃** (Iron(III) hydroxide), which is a precipitate.
- **NaOH** (Sodium hydroxide), which is a strong base.

**Hint:** Always start by identifying the reactants involved in the reaction.

### Step 2: Understand the Nature of Fe(OH)₃
Fe(OH)₃ is known to be an insoluble precipitate in water. This means that it does not dissolve readily in aqueous solutions.

**Hint:** Remember that precipitates are typically insoluble in water, which affects their reactivity.

### Step 3: Consider the Reaction with Excess NaOH
When NaOH is added in excess to Fe(OH)₃, we need to consider whether any reaction occurs. In some cases, hydroxides can dissolve in strong bases to form soluble complexes. However, this is not the case with Fe(OH)₃.

**Hint:** Think about whether the hydroxide can form a soluble complex with the base.

### Step 4: Compare with Other Hydroxides
For example, when aluminum hydroxide (Al(OH)₃) reacts with NaOH, it can form a soluble complex (like [Al(OH)₄]⁻). However, Fe(OH)₃ does not have a similar tendency to form such complexes.

**Hint:** Compare the behavior of different metal hydroxides to understand their reactivity with bases.

### Step 5: Conclude No Reaction
Since Fe(OH)₃ does not react with excess NaOH to form any soluble complex or any other product, we conclude that there is no reaction.

**Hint:** If no products are formed and no changes occur, it indicates that the reaction does not proceed.

### Final Answer
The reaction between Fe(OH)₃ and excess NaOH results in **no reaction**.