`K_(4)[Fe(CN)_(6)]+ZnSO_(4) to Zn_(2)[Fe(CN)_(6)]darr`

Options

A. For precipitate formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction for the equation \( K_4[Fe(CN)_6] + ZnSO_4 \rightarrow Zn_2[Fe(CN)_6] \), we will analyze the components and the nature of the products formed.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in the equation are \( K_4[Fe(CN)_6] \) (potassium ferrocyanide) and \( ZnSO_4 \) (zinc sulfate).

2. **Identify the Products**:
- The product formed is \( Zn_2[Fe(CN)_6] \) (zinc ferrocyanide).

3. **Analyze the Reaction**:
- In this reaction, zinc ions from zinc sulfate are reacting with the ferrocyanide ions from potassium ferrocyanide to form zinc ferrocyanide.

4. **Check for Precipitate Formation**:
- The notation \( \downarrow \) next to \( Zn_2[Fe(CN)_6] \) indicates that this product is a precipitate. This means it is insoluble in the reaction medium.

5. **Determine the Type of Reaction**:
- Since a precipitate is formed as a result of the reaction, this is classified as a **precipitate formation reaction**.

### Final Answer:
The reaction \( K_4[Fe(CN)_6] + ZnSO_4 \rightarrow Zn_2[Fe(CN)_6] \) is a **precipitate formation reaction**.

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