`3PbSdarr+8HNO_(3)(dil.)to3Pb(NO_(3))_(2)+3S+2NOuarr`

Options

A. For precipitate formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To analyze the given chemical reaction and determine its type, we can follow these steps:

### Step 1: Identify the Reactants and Products
The reaction provided is:
\[ 3 \text{PbS} + 8 \text{HNO}_3 \text{ (dil.)} \rightarrow 3 \text{Pb(NO}_3\text{)}_2 + 3 \text{S} + 2 \text{NO} \]

- **Reactants**: Lead(II) sulfide (PbS) and dilute nitric acid (HNO3).
- **Products**: Lead(II) nitrate (Pb(NO3)2), sulfur (S), and nitrogen monoxide (NO).

### Step 2: Analyze the Reactants
In the reactants, we have PbS, which is a solid precipitate. The notation "PbS" with a downward arrow indicates that it is indeed a precipitate.

### Step 3: Analyze the Products
In the products, we have:
- Pb(NO3)2, which is soluble in water.
- Sulfur (S), which is a solid.
- Nitrogen monoxide (NO), which is a gas (indicated by the upward arrow).

### Step 4: Determine the Type of Reaction
Since we have a precipitate (PbS) in the reactants that is dissolving (as it transforms into soluble Pb(NO3)2) and producing gases (NO), we can classify this reaction.

- The presence of a precipitate in the reactants and the absence of any precipitate in the products indicates that the precipitate is dissolving.
- The formation of gases also supports the idea that this is a reaction involving a change in state.

### Conclusion
Based on the analysis, the reaction can be classified as a **precipitate dissolution reaction**.