`2AgF+MgCl_(2) to MgF_(2) darr+2AgCldarr`

Options

A. For precipitate formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction given by the equation \(2 \text{AgF} + \text{MgCl}_2 \rightarrow \text{MgF}_2 \downarrow + 2 \text{AgCl} \downarrow\), we can follow these steps:

### Step 1: Identify the Reactants and Products
The reactants in this reaction are:
- \(2 \text{AgF}\) (Silver fluoride)
- \(\text{MgCl}_2\) (Magnesium chloride)

The products of the reaction are:
- \(\text{MgF}_2\) (Magnesium fluoride)
- \(2 \text{AgCl}\) (Silver chloride)

### Step 2: Analyze the Reaction
In this reaction, we can see that:
- Silver fluoride (\( \text{AgF} \)) reacts with magnesium chloride (\( \text{MgCl}_2 \)).
- The products formed are magnesium fluoride (\( \text{MgF}_2 \)) and silver chloride (\( \text{AgCl} \)).

### Step 3: Look for Precipitate Formation
The downward arrows (↓) next to \( \text{MgF}_2 \) and \( \text{AgCl} \) indicate that these compounds are precipitates. This means they are insoluble in the reaction medium and will form solid particles.

### Step 4: Classify the Reaction
Since precipitates are formed in the product side of the reaction, we classify this reaction as a **precipitate formation reaction**.

### Conclusion
The type of reaction is a **precipitate formation reaction**.

---