`FeCl_(3)+Na_(3)PO_(4) to FePO_(4)darr+3NaCl`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the given reaction \( \text{FeCl}_3 + \text{Na}_3\text{PO}_4 \rightarrow \text{FePO}_4 \downarrow + 3\text{NaCl} \), we will analyze the reaction step by step and determine its type.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Iron(III) chloride (\( \text{FeCl}_3 \))
- Sodium phosphate (\( \text{Na}_3\text{PO}_4 \))

### Step 2: Identify the Products
The products of the reaction are:
- Iron(III) phosphate (\( \text{FePO}_4 \)), which is indicated by the downward arrow (precipitate)
- Sodium chloride (\( \text{NaCl} \))

### Step 3: Analyze the Reaction
In this reaction, we observe that:
- The reactants are both soluble in water.
- The product \( \text{FePO}_4 \) is formed as a precipitate, which means it is insoluble in water.

### Step 4: Determine the Type of Reaction
Since a precipitate is formed from the reactants, we can classify this reaction as a **precipitate formation reaction**. This means that initially, there was no precipitate present at the reactant side, but as the reaction proceeds, a precipitate is formed at the product side.

### Conclusion
Thus, the type of reaction for the given equation \( \text{FeCl}_3 + \text{Na}_3\text{PO}_4 \rightarrow \text{FePO}_4 \downarrow + 3\text{NaCl} \) is a **precipitate formation reaction**.

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