`BaCO_(3)darr+2AcOH to Ba(AcO)_(2)+CO_(2)uarr+H_(2)O`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction represented by the equation:

\[ \text{BaCO}_3 (s) + 2 \text{AcOH} \rightarrow \text{Ba(AcO)}_2 (aq) + \text{CO}_2 (g) + \text{H}_2O (l) \]

we can analyze the components involved in the reaction step by step.

### Step 1: Identify the Reactants and Products
- **Reactants**: Barium carbonate (\( \text{BaCO}_3 \)) and acetic acid (\( \text{AcOH} \)).
- **Products**: Barium acetate (\( \text{Ba(AcO)}_2 \)), carbon dioxide (\( \text{CO}_2 \)), and water (\( \text{H}_2O \)).

### Step 2: Analyze the State of Each Component
- **Barium carbonate (\( \text{BaCO}_3 \))** is indicated with a downward arrow, which signifies that it is a solid precipitate.
- **Acetic acid (\( \text{AcOH} \))** is in aqueous form, meaning it is dissolved in water.
- **Barium acetate (\( \text{Ba(AcO)}_2 \))** is indicated as aqueous, meaning it is soluble in water.
- **Carbon dioxide (\( \text{CO}_2 \))** is indicated with an upward arrow, which signifies that it is a gas.
- **Water (\( \text{H}_2O \))** is in liquid form.

### Step 3: Determine the Type of Reaction
In this reaction:
- The solid precipitate \( \text{BaCO}_3 \) reacts with acetic acid to form \( \text{Ba(AcO)}_2 \) (which is soluble in water), \( \text{CO}_2 \) (which is released as a gas), and \( \text{H}_2O \).
- The presence of a solid precipitate on the reactant side and the formation of soluble products indicates that the precipitate is dissolving in the reaction.

### Conclusion
Since we have a solid precipitate that is dissolving and forming soluble products along with a gas, this reaction is classified as a **precipitate dissolution reaction**.

---