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PbO(2) ↓+HNO(3)("Conc.") to Pb(NO(3))(2)...

`PbO_(2) ↓+HNO_(3)("Conc.") to Pb(NO_(3))_(2)+H_(2)O+[O]`

A

For precipitate formation formation reaction

B

For precipitate dissolution reaction

C

For precipitate exchange reaction

D

For no reaction

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The correct Answer is:
To determine the type of reaction for the given equation \( \text{PbO}_2 + \text{HNO}_3(\text{Conc.}) \rightarrow \text{Pb(NO}_3)_2 + \text{H}_2\text{O} + [\text{O}] \), we can follow these steps: ### Step 1: Identify the Reactants and Products The reactants are lead(IV) oxide (\( \text{PbO}_2 \)) and concentrated nitric acid (\( \text{HNO}_3 \)). The products are lead(II) nitrate (\( \text{Pb(NO}_3)_2 \)), water (\( \text{H}_2\text{O} \)), and nascent oxygen (\( [\text{O}] \)). ### Step 2: Analyze the State of Reactants and Products - **Reactants**: \( \text{PbO}_2 \) is a solid precipitate (indicated by the downward arrow). - **Products**: \( \text{Pb(NO}_3)_2 \) is soluble in water, \( \text{H}_2\text{O} \) is also soluble, and nascent oxygen is a gaseous product. ### Step 3: Determine the Reaction Type In this reaction: - The solid lead(IV) oxide (\( \text{PbO}_2 \)) is reacting with concentrated nitric acid. - The solid precipitate (\( \text{PbO}_2 \)) is being converted into soluble lead(II) nitrate (\( \text{Pb(NO}_3)_2 \)). - This indicates that the solid precipitate is dissolving into a soluble form. ### Conclusion Since a solid precipitate (\( \text{PbO}_2 \)) is dissolving to form soluble products, this reaction is classified as a **precipitate dissolution reaction**. ### Final Answer The type of reaction is **B: Precipitate Dissolution Reaction**. ---
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VK JAISWAL ENGLISH-TYPES OF REACTIONS-SUBJECTIVE PROBLEMS
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