`underline(S)O_(2)+H_(2)O to H_(2)SO_(3)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To determine whether the product of the reaction \( SO_2 + H_2O \) to form \( H_2SO_3 \) is an oxoacid and to identify the appropriate suffix used in its naming, we can follow these steps:

### Step 1: Identify the Reactants and Products
The reactants in the reaction are sulfur dioxide (\( SO_2 \)) and water (\( H_2O \)). The product formed is sulfurous acid (\( H_2SO_3 \)).

### Step 2: Determine the Nature of the Product
Next, we need to check if \( H_2SO_3 \) is an oxoacid. An oxoacid is defined as an acid that contains oxygen, hydrogen, and another element (in this case, sulfur). Since \( H_2SO_3 \) contains all three elements (H, O, and S), it qualifies as an oxoacid.

### Step 3: Identify the Oxidation State of Sulfur
To name the oxoacid, we should determine the oxidation state of sulfur in \( H_2SO_3 \). In \( H_2SO_3 \):
- Each hydrogen (H) has an oxidation state of +1.
- Oxygen (O) typically has an oxidation state of -2.

Let \( x \) be the oxidation state of sulfur (S). The equation for the oxidation states can be set up as follows:

\[ 2(+1) + x + 3(-2) = 0 \]
\[ 2 + x - 6 = 0 \]
\[ x - 4 = 0 \implies x = +4 \]

Thus, the oxidation state of sulfur in \( H_2SO_3 \) is +4.

### Step 4: Naming the Oxoacid
The naming of oxoacids is based on the oxidation state of the central atom (in this case, sulfur). Since the oxidation state of sulfur is +4, the suffix used for the oxoacid is “-ous.” Therefore, \( H_2SO_3 \) is named sulfurous acid.

### Step 5: Conclusion
Based on the analysis, we conclude that \( H_2SO_3 \) is indeed an oxoacid, and it is named sulfurous acid.

### Final Answer
The product \( H_2SO_3 \) is an oxoacid, and it is named sulfurous acid.

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