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underline(I)F(7)+H(2)O to HIO(4)+HF...

`underline(I)F_(7)+H_(2)O to HIO_(4)+HF`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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AI Generated Solution

The correct Answer is:
To analyze the reaction \( IF_7 + H_2O \rightarrow HIO_4 + HF \) and determine the correct classification of the products, we can follow these steps: ### Step 1: Identify the Reactants and Products We start with the reactants: - \( IF_7 \) (iodine heptafluoride) - \( H_2O \) (water) The products are: - \( HIO_4 \) (metaperiodic acid) - \( HF \) (hydrofluoric acid) ### Step 2: Determine the Nature of the Products Next, we need to analyze the products to see if they qualify as oxyacids. #### Analyzing \( HIO_4 \): 1. **Check for Hydrogen, Oxygen, and Other Elements**: - \( HIO_4 \) contains: - Hydrogen (H) - Oxygen (O) - Iodine (I) as the other element. - This satisfies the first condition of being an oxyacid. 2. **Check for Dissociable Hydrogen**: - The structure of \( HIO_4 \) can be represented as: - \( I \) bonded to four \( O \) atoms, with one \( O \) atom bonded to \( H \) (i.e., \( OH \)). - This \( OH \) group can dissociate to release \( H^+ \) ions, satisfying the second condition. Thus, \( HIO_4 \) qualifies as an oxyacid with an "ic" suffix. #### Analyzing \( HF \): - \( HF \) is hydrofluoric acid, which is not an oxyacid since it does not contain oxygen. It is a binary acid. ### Step 3: Classify the Products From the analysis: - \( HIO_4 \) is an oxyacid with an "ic" suffix. - \( HF \) is not an oxyacid. ### Step 4: Choose the Correct Option Given the options: 1. If the product is an oxyacid with "ic" suffix. 2. If the product is an oxyacid with "ous" suffix. 3. If one product is an oxyacid with "ous" suffix and the other with "ic" suffix. 4. If the product is neither an oxyacid nor has any suffix. The correct classification based on our analysis is: - **Option 1**: The product \( HIO_4 \) is an oxyacid with an "ic" suffix. ### Final Answer: **The correct option is: If the product is an oxyacid with "ic" suffix.** ---
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