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underline(C)IF(5)+H(2)O to HClO(3)+HF...

`underline(C)IF_(5)+H_(2)O to HClO_(3)+HF`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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The correct Answer is:
To determine the type of reaction represented by the equation \( \text{ClF}_5 + \text{H}_2\text{O} \rightarrow \text{HClO}_3 + \text{HF} \), we will analyze the products and their characteristics step by step. ### Step 1: Identify the Reactants and Products The reactants in this reaction are: - \( \text{ClF}_5 \) (Chlorine pentafluoride) - \( \text{H}_2\text{O} \) (Water) The products are: - \( \text{HClO}_3 \) (Chloric acid) - \( \text{HF} \) (Hydrofluoric acid) ### Step 2: Analyze the Products Next, we need to determine if the products are oxyacids. An oxyacid must meet the following criteria: 1. It must contain hydrogen (H), oxygen (O), and at least one other element (E). 2. At least one hydrogen atom must be bonded to an oxygen atom in such a way that it can dissociate to release \( \text{H}^+ \) ions. #### Analyzing \( \text{HClO}_3 \): - Contains H, O, and Cl (the other element). - The structure of \( \text{HClO}_3 \) shows that it has an OH group, which means it can dissociate to release \( \text{H}^+ \). Thus, \( \text{HClO}_3 \) is an oxyacid. #### Analyzing \( \text{HF} \): - Contains H and F but does not contain O. - Therefore, \( \text{HF} \) is not an oxyacid. ### Step 3: Determine the Type of Reaction Since one of the products is an oxyacid (\( \text{HClO}_3 \)) and the other product (\( \text{HF} \)) is not an oxyacid, we need to consider the options provided: - **Option A**: Product is oxyacid with X suffix. - **Option B**: Product is oxyacid with O suffix. - **Option C**: Products are two oxyacids, one with X suffix and the other with O suffix. - **Option D**: Product is not an oxyacid. Given that \( \text{HClO}_3 \) is an oxyacid and \( \text{HF} \) is not, the correct option would be **Option A**: Product is oxyacid with X suffix (as \( \text{HClO}_3 \) has the suffix "ic"). ### Final Answer The correct answer is **Option A**: Product is oxyacid with X suffix. ---
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