`underline(B)rF_(5)+H_(2)O to HBrO_(3)+HF`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To analyze the reaction \( \text{BrF}_5 + \text{H}_2\text{O} \rightarrow \text{HBrO}_3 + \text{HF} \) and determine the correct classification of the products, we can follow these steps:

### Step 1: Identify the Reactants and Products
- The reactants are \( \text{BrF}_5 \) (Bromine pentafluoride) and \( \text{H}_2\text{O} \) (water).
- The products are \( \text{HBrO}_3 \) (bromic acid) and \( \text{HF} \) (hydrofluoric acid).

### Step 2: Determine the Nature of the Products
- We need to check if the products are oxyacids. An oxyacid must contain:
1. Hydrogen (H) atoms.
2. Oxygen (O) atoms.
3. At least one other element (E), which can be a metal or non-metal.

### Step 3: Analyze \( \text{HBrO}_3 \)
- The structure of \( \text{HBrO}_3 \) includes:
- 1 hydrogen atom.
- 3 oxygen atoms.
- 1 bromine atom.
- It satisfies the conditions of an oxyacid:
- It contains H and O.
- The H is bonded to O, which can dissociate to form \( \text{H}^+ \) ions.

### Step 4: Analyze \( \text{HF} \)
- The structure of \( \text{HF} \) includes:
- 1 hydrogen atom.
- 1 fluorine atom.
- It does not satisfy the conditions of an oxyacid because it lacks oxygen.

### Step 5: Conclusion
- Since \( \text{HBrO}_3 \) is an oxyacid (specifically, bromic acid with the "ic" suffix) and \( \text{HF} \) is not an oxyacid, we conclude that there is only one oxyacid product in this reaction.

### Step 6: Choose the Correct Option
- Based on the analysis, the correct option is:
- **Option A**: The product is an oxyacid with "ic" suffix (bromic acid).