`underline(I)F_(5)+H_(2)O to HIO_(3)+HF`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To analyze the reaction \( IF_5 + H_2O \rightarrow HIO_3 + HF \) and determine the nature of the products, we will follow these steps:

### Step 1: Identify the reactants and products
The reactants in this reaction are:
- \( IF_5 \) (Iodine pentafluoride)
- \( H_2O \) (Water)

The products are:
- \( HIO_3 \) (Iodic acid)
- \( HF \) (Hydrofluoric acid)

### Step 2: Determine if the products are oxyacids
An oxyacid is defined by two main criteria:
1. It must contain hydrogen (H), oxygen (O), and at least one other element (E).
2. It must have at least one hydrogen atom bonded to an oxygen atom that can dissociate to release \( H^+ \) ions.

#### Analyzing \( HIO_3 \):
- **Contains H, O, and I**: Yes, it has hydrogen, oxygen, and iodine.
- **Has H bonded to O**: Yes, the structure of \( HIO_3 \) includes an -OH group. If the bond between H and O is broken, it can release \( H^+ \).

Thus, \( HIO_3 \) meets both criteria and is classified as an oxyacid, specifically iodic acid, which has the suffix "ic".

#### Analyzing \( HF \):
- **Contains H and F**: Yes, it has hydrogen and fluorine.
- **Contains O**: No, it does not contain oxygen.

Since \( HF \) lacks oxygen, it does not qualify as an oxyacid.

### Step 3: Conclusion
Based on the analysis:
- We have one product that is an oxyacid with an "ic" suffix (\( HIO_3 \)).
- The other product (\( HF \)) is not an oxyacid.

### Final Answer
The correct option is: **The product is an oxyacid with an "ic" suffix.**

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