`H_(2)underline(S)O_(5)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( H_2SO_5 + H_2O \rightarrow H_2SO_4 + H_2O_2 \), we will analyze the components involved and identify the type of reaction taking place.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are \( H_2SO_5 \) (peroxy acid, known as peroxymonosulfuric acid or Caro's acid) and \( H_2O \) (water).

2. **Understanding the Structure of \( H_2SO_5 \)**:
- \( H_2SO_5 \) contains a peroxy linkage (–O–O–) in its structure. This is crucial because it indicates that the compound can release oxygen when it reacts.

3. **Reaction with Water**:
- When \( H_2SO_5 \) reacts with water, it undergoes hydrolysis. The peroxy acid breaks down to form sulfuric acid (\( H_2SO_4 \)) and hydrogen peroxide (\( H_2O_2 \)).

4. **Write the Balanced Equation**:
- The balanced chemical equation for the reaction is:
\[ H_2SO_5 + H_2O \rightarrow H_2SO_4 + H_2O_2 \]

5. **Identify the Type of Reaction**:
- This reaction is a **decomposition reaction** where a single compound (peroxy acid) breaks down into two products (sulfuric acid and hydrogen peroxide).

6. **Conclusion**:
- The products formed are sulfuric acid, which is a strong acid and a well-known chemical, and hydrogen peroxide, which is used as a bleaching agent and disinfectant.