`H_(4)underline(B_(2))O_(6)+H_(2)O to H_(3)BO_(3)+H_(2)O_(2)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given chemical reaction:

**Reaction:**
\[ H_4B_2O_6 + H_2O \rightarrow H_3BO_3 + H_2O_2 \]

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- The reactants are \( H_4B_2O_6 \) (which is boric acid) and \( H_2O \) (water).
- The products are \( H_3BO_3 \) (boric acid) and \( H_2O_2 \) (hydrogen peroxide).

2. **Analyze the Reactants:**
- \( H_4B_2O_6 \) is a boron-containing compound. It can be considered as a precursor to boric acid.
- When it reacts with water, it can break down to form boric acid and hydrogen peroxide.

3. **Identify the Type of Reaction:**
- This reaction can be classified as a **decomposition reaction** where a single compound (boron compound) breaks down into two products (boric acid and hydrogen peroxide).

4. **Determine the Nature of Products:**
- \( H_3BO_3 \) is an oxyacid because it contains hydrogen, oxygen, and boron.
- \( H_2O_2 \) is not classified as an oxyacid since it only contains hydrogen and oxygen without any other element.

5. **Naming the Oxyacid:**
- The oxyanion derived from \( H_3BO_3 \) is \( BO_3^{3-} \) (borate).
- Since the oxyanion ends with "ate", the corresponding acid is named using the suffix "ic", making it **boric acid**.

6. **Conclusion:**
- The reaction produces one oxyacid (boric acid) and one compound that is not an oxyacid (hydrogen peroxide).
- Therefore, the correct option is that the product is an oxyacid with the "ic" suffix.

### Final Answer:
The correct option is that the product is an oxyacid with the "ic" suffix, specifically **boric acid**.