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H(2)underline(S(2))O(8)+H(2)O to H(2)SO(...

`H_(2)underline(S_(2))O_(8)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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The correct Answer is:
To solve the question regarding the reaction of H₂S₂O₈ with H₂O to form H₂SO₄ and H₂O₂, we will analyze the products to determine if they are oxyacids and identify their suffixes. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reactants are H₂S₂O₈ (disulfuric acid) and H₂O (water). - The products are H₂SO₄ (sulfuric acid) and H₂O₂ (hydrogen peroxide). 2. **Check if the Products are Oxyacids**: - **Definition of Oxyacid**: An oxyacid must contain oxygen, hydrogen, and at least one other element. Additionally, it must have at least one oxygen-hydrogen bond. 3. **Analyze H₂SO₄**: - **Composition**: H₂SO₄ contains hydrogen (H), sulfur (S), and oxygen (O). - **Oxygen-Hydrogen Bonds**: H₂SO₄ has two oxygen-hydrogen bonds (the OH groups). - **Conclusion**: H₂SO₄ qualifies as an oxyacid. It is commonly known as sulfuric acid, which has the suffix "IC". 4. **Analyze H₂O₂**: - **Composition**: H₂O₂ contains only hydrogen (H) and oxygen (O). - **Oxygen-Hydrogen Bonds**: H₂O₂ has two oxygen-hydrogen bonds. - **Conclusion**: H₂O₂ does not qualify as an oxyacid because it lacks another element besides hydrogen and oxygen. 5. **Summarize the Findings**: - H₂SO₄ is an oxyacid with the "IC" suffix (sulfuric acid). - H₂O₂ is not an oxyacid. 6. **Final Answer**: - The correct statement is that the product is an oxyacid with the "IC" suffix (H₂SO₄).
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