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underline(I)Cl+H(2)O to HIO+HCl...

`underline(I)Cl+H_(2)O to HIO+HCl`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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The correct Answer is:
To solve the question regarding the reaction of ICl with H2O to form HIO and HCl, we will analyze the products formed and determine if they are oxyacids, and if so, what their suffixes are. ### Step-by-Step Solution: 1. **Identify the Reactants and Products:** - Reactants: ICl (Iodine monochloride) and H2O (Water) - Products: HIO (Hypoiodous acid) and HCl (Hydrochloric acid) 2. **Check the Structure of the Products:** - **HIO (Hypoiodous acid):** - Contains: Oxygen (O), Hydrogen (H), and Iodine (I). - It satisfies the conditions for being an oxyacid: - It has oxygen, hydrogen, and at least one other element (iodine). - It has an oxygen-hydrogen bond (O-H bond). - **HCl (Hydrochloric acid):** - Contains: Hydrogen (H) and Chlorine (Cl). - It does not satisfy the conditions for being an oxyacid: - It lacks oxygen, which is essential for an oxyacid. 3. **Determine the Type of Acid:** - Since HIO meets the criteria for an oxyacid, it is classified as such. - The name of HIO is hypoiodous acid, which has the suffix "OUS." - HCl is not an oxyacid. 4. **Conclusion:** - There is only one oxyacid produced in this reaction, which is HIO (hypoiodous acid). - The suffix for this oxyacid is "OUS." 5. **Select the Correct Option:** - Based on the analysis: - The correct option is that the product is an oxyacid with the OUS suffix (hypoiodous acid).
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