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underline(B(2))H(6)+H(2)O to H(3)BO(3)+H...

`underline(B_(2))H_(6)+H_(2)O to H_(3)BO_(3)+H_(2)uarr`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Text Solution

AI Generated Solution

The correct Answer is:
To solve the reaction \( B_2H_6 + H_2O \rightarrow H_3BO_3 + H_2 \), we will analyze the reactants and products step by step. ### Step 1: Identify the Reactants The reactants in this reaction are: - \( B_2H_6 \) (Diborane) - \( H_2O \) (Water) ### Step 2: Identify the Products The products of the reaction are: - \( H_3BO_3 \) (Boric acid) - \( H_2 \) (Hydrogen gas) ### Step 3: Determine the Nature of the Reaction This reaction can be classified as a hydrolysis reaction where diborane reacts with water to form boric acid and hydrogen gas. ### Step 4: Analyze the Product \( H_3BO_3 \) - \( H_3BO_3 \) is an oxyacid because it contains hydrogen, oxygen, and boron (the other element). - In oxyacids, the hydrogen is bonded to oxygen, and upon dissociation, it releases protons (H⁺) and anions. ### Step 5: Naming the Oxyacid - The anion of boric acid is \( BO_3^{3-} \), which is called borate. - Since the anion ends in "-ate," the corresponding acid name will end in "-ic." Therefore, \( H_3BO_3 \) is named boric acid. ### Step 6: Analyze the Other Product \( H_2 \) - \( H_2 \) is simply hydrogen gas and does not qualify as an oxyacid because it does not contain oxygen or any other elements besides hydrogen. ### Step 7: Conclusion In this reaction, we have one product that is an oxyacid (boric acid) and one product that is not an oxyacid (hydrogen gas). Thus, the correct classification of the products is that we have an oxyacid with the "-ic" suffix and one product that is not an oxyacid. ### Final Answer The correct option is that the product is an oxyacid with the "-ic" suffix (boric acid). ---
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