`underline(S_(8))+H_(2)O to ` No reaction.

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the question regarding the reaction between \( S_8 \) and \( H_2O \), we will analyze the situation step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this case are \( S_8 \) (octasulfur) and \( H_2O \) (water).

2. **Analyze the Reaction**: When \( S_8 \) is mixed with \( H_2O \), we need to determine if any chemical reaction occurs. In this case, \( S_8 \) does not react with water under normal conditions.

3. **Conclusion on Reaction**: Since there is no reaction between \( S_8 \) and \( H_2O \), we conclude that no products are formed from this interaction.

4. **Determine the Type of Product**: Since there are no products formed, we cannot classify any product as an oxyacid or any other type of acid.

5. **Select the Correct Option**: Given the options provided, the correct choice is that there is no product formed, which means it cannot be classified as an oxyacid (neither with IC suffix nor with OUS suffix). Therefore, the answer is option 4: "the product is not an oxyacid, neither with IC suffix nor with OUS suffix."

### Final Answer:
The answer to the question is option 4: "the product is not an oxyacid, neither with IC suffix nor with OUS suffix."

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