`underline(F_(2))+H_(2)O to HF+O_(2)` (Ozonide oxygen)

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the question regarding the reaction of \( F_2 \) with \( H_2O \) to form \( HF \) and \( O_2 \), we need to determine whether the products are oxyacids. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the Reactants and Products
The reaction given is:
\[ F_2 + H_2O \rightarrow HF + O_2 \]

**Reactants:**
- \( F_2 \) (Fluorine gas)
- \( H_2O \) (Water)

**Products:**
- \( HF \) (Hydrofluoric acid)
- \( O_2 \) (Oxygen gas)

### Step 2: Define Oxyacids
An oxyacid is a type of acid that contains:
1. Hydrogen (H)
2. Oxygen (O)
3. At least one other element (usually a non-metal).

Additionally, an oxyacid must have at least one oxygen-hydrogen bond (O-H bond).

### Step 3: Analyze the Products
Now, we will analyze each product to see if they qualify as oxyacids.

**Product 1: \( HF \)**
- Composition: \( HF \) contains Hydrogen and Fluorine but **no Oxygen**.
- Conclusion: Since it lacks Oxygen, \( HF \) is **not an oxyacid**.

**Product 2: \( O_2 \)**
- Composition: \( O_2 \) contains only Oxygen and **no Hydrogen**.
- Conclusion: Since it lacks Hydrogen, \( O_2 \) is **not an oxyacid**.

### Step 4: Conclusion
Since neither \( HF \) nor \( O_2 \) qualifies as an oxyacid, we conclude that:
- The products of the reaction do not form any oxyacids.

### Final Answer
The correct option is:
- The products are not oxyacids, neither with IC suffix nor with OUS suffix.

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