`Na(s)+H_(2)O(l) overset(R.T.) to NaOH +H_(2) uarr`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To solve the given reaction \( \text{Na}(s) + \text{H}_2\text{O}(l) \overset{R.T.}{\rightarrow} \text{NaOH} + \text{H}_2 \), we will analyze it step by step.

### Step 1: Identify the Reactants and Products
The reactants in this reaction are sodium (Na) and water (H2O). The products formed are sodium hydroxide (NaOH) and hydrogen gas (H2).

### Step 2: Classify the Reaction
This reaction is classified as a displacement reaction. In this type of reaction, a more reactive element displaces a less reactive element from a compound. Here, sodium (Na) is more reactive than hydrogen (H) in water, so it displaces hydrogen.

### Step 3: Write the Reaction in a More Understandable Form
We can rewrite the reaction for clarity:
\[ \text{Na} + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{H}_2 \]
This shows that sodium reacts with water to produce sodium hydroxide and hydrogen gas.

### Step 4: Analyze Oxidation States
- Sodium (Na) in elemental form has an oxidation state of 0.
- In water (H2O), hydrogen (H) has an oxidation state of +1, and oxygen (O) has an oxidation state of -2.
- In sodium hydroxide (NaOH), sodium (Na) has an oxidation state of +1, and hydroxide (OH) has an overall charge of -1 (with O at -2 and H at +1).
- Hydrogen gas (H2) has an oxidation state of 0.

### Step 5: Determine Oxidation and Reduction
- Sodium (Na) is oxidized from 0 to +1.
- Hydrogen (H) is reduced from +1 in water to 0 in hydrogen gas.

### Step 6: Identify the Type of Reaction
This reaction is a redox reaction because it involves both oxidation (sodium losing electrons) and reduction (hydrogen gaining electrons).

### Step 7: Conclusion
The reaction is a displacement reaction and also a redox reaction. It is not a disproportionation reaction because no single species is undergoing both oxidation and reduction simultaneously. It is also not a comproportionation reaction since different species are involved.

### Final Answer
The reaction \( \text{Na}(s) + \text{H}_2\text{O}(l) \rightarrow \text{NaOH} + \text{H}_2 \) is a displacement reaction and a redox reaction.

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