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MnO(2)+2KOH+(1)/(2)O(2) to K(2)MnO(4)+H(...

`MnO_(2)+2KOH+(1)/(2)O_(2) to K_(2)MnO_(4)+H(2)O`

A

For disproportionation reaction.

B

For comproportionation reaction.

C

For either intermolecular redox reaction or displacement reaction

D

For either thermal combination redox reaction or thermal decomposition redox reaction.

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The correct Answer is:
To solve the given reaction and classify it, we will follow these steps: ### Step 1: Write down the reaction The reaction provided is: \[ \text{MnO}_2 + 2 \text{KOH} + \frac{1}{2} \text{O}_2 \rightarrow \text{K}_2\text{MnO}_4 + \text{H}_2\text{O} \] ### Step 2: Determine the oxidation states of each element 1. **For MnO2**: - Manganese (Mn) has an oxidation state of +4 (since \( X + 2(-2) = 0 \) gives \( X = +4 \)). - Oxygen (O) has an oxidation state of -2. 2. **For KOH**: - Potassium (K) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. - Hydrogen (H) has an oxidation state of +1. 3. **For O2**: - Oxygen (O) has an oxidation state of 0 (elemental state). 4. **For K2MnO4**: - Potassium (K) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. - To find Mn, we set up the equation: \[ 2(+1) + X + 4(-2) = 0 \] \[ 2 + X - 8 = 0 \] \[ X = +6 \] (Mn has an oxidation state of +6). 5. **For H2O**: - Hydrogen (H) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. ### Step 3: Analyze the changes in oxidation states - **Manganese**: Changes from +4 in MnO2 to +6 in K2MnO4 (oxidation). - **Oxygen**: Changes from 0 in O2 to -2 in H2O (reduction). ### Step 4: Identify the type of reaction Since there is a change in oxidation states where Mn is oxidized and O is reduced, this reaction is classified as a **redox reaction** (oxidation-reduction reaction). ### Step 5: Determine if it is a disproportionation or comproportionation reaction - **Disproportionation**: A single species is both oxidized and reduced. This is not the case here since two different species are involved. - **Comproportionation**: A single species in two different oxidation states reacts to form a single product. This is also not the case here. ### Conclusion The reaction is a redox reaction, specifically an intermolecular redox reaction, as different species are involved in oxidation and reduction. ### Final Answer The correct classification of the reaction is that it is a **redox reaction**. ---
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